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saveliy_v [14]
3 years ago
12

If Michael Jordan has a vertical leap of 1.29 meters, what is his take-off speed and his hang time (total time to move upwards t

o the peak and then return to the ground)?
Physics
1 answer:
evablogger [386]3 years ago
6 0
(Hint: the time<span> to rise to the </span>peak<span>is one-half the </span>total hang-time<span>.).</span>
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Light travels at 300,000,000 m/s. This is an example
mafiozo [28]

Answer:

ook soooooo

Explanation:

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2 years ago
The gravity on planet Ais 15.6 m/s the mass of an object is 740 grams, what is the weight of the
Jobisdone [24]

Explanation:

W = mg

m = 740g = 740/1000kg = 0.74kg

g = 15.6ms^-2

W = 0.74x15.6

W = 11.544 N

4 0
3 years ago
Which theory of language development and acquisition includes the concepts of reinforcement, stimuli control, deprivation, and a
uranmaximum [27]

The answer is: a. Skinner’s idea of language

<span>Skinner was a psychologists and one of the first behaviorists. In his language acquisition theory, he states that language acquisition is an environmental and social phenomenon; therefore, children acquire language through operant conditioning, which includes stimuli control, reinforcement (positive and aversive), and deprivation.</span>

6 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
stepladder [879]

Answer:  well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.  

The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]  

so t = sqrt(2*100/9.8) = 4.52s.  

The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s  

The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.  

so the final velocity is = sqrt(44.3^2 + 14.4^2) = 46.6m/s

Explanation: yes

6 0
3 years ago
Read 2 more answers
Coherent light with wavelength 597 nm passes through two very narrow slits, and theinterference pattern is observed on a screen
velikii [3]

Answer:

The required wavelength is 1.19 μm

Explanation:

In the double-slit study, the formula below determines the position of light fringes y_m on-screen.

y_m = \dfrac{m \lambda D}{d}

where;

m = fringe order

d = slit separation

λ = wavelength

D = distance between screen to the source

For the first bright fringe, m = 1, and we make (d) the subject, we have:

d = \dfrac{(1) \lambda D}{y_1}

d = \dfrac{ \lambda D}{y_1}

replacing the value from the given question, we get:

d = \dfrac{ (597 \ nm )\times (3.00 \  m)}{4.84 \ mm} \\ \\ d = \dfrac{ (597 \ nm \times (\dfrac{1 \ m}{10^9\ nm}) )\times (3.00 \  m)}{4.84 \ mm(\dfrac{1 \ m}{1000 \ mm })} \\ \\  d = 3.7 \times 10^{-4}  \ m

In the double-slit study, the formula which illustrates the position of dark fringes y_m on-screen can be illustrated as:

y_m = (m+\dfrac{1}{2}) \dfrac{\lambda D}{d}

The value of m in the dark fringe first order = 0

∴

y_0 = (0+\dfrac{1}{2}) \dfrac{\lambda D}{d}

y_0 = (\dfrac{1}{2}) \dfrac{\lambda D}{d}

making λ the subject of the formula, we have:

\lambda = \dfrac{2y_o d}{D} \\ \\ \lambda = \dfrac{2(4.84 \  mm) \times \dfrac{1 \ m}{1000 \ mm} (3.7 \times 10^{-4}  \ m) }{3.00 \ m}

\lambda = 1.19 \times 10^{-6}  \ m ( \dfrac{10^6 \mu m }{1\ m}) \\ \\ \lambda = 1.19 \mu m

5 0
3 years ago
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