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3 years ago

Which example has the least kinetic energy

Physics

1 answer:

Stells [14]3 years ago

5 0

Answer:

Explanation:

Let’s calculate the kinetic energy for all of the choices.

a. (1/2)(100)(100)^2 = 50(10000)=500,000

b. (1/2)(100)(1)^2 = 50

c. (1/2)(10)(100)^2 = 5(10000) = 50,000

d. (1/2)(1)(1)^2 = 0.5

We can see that (d) has the least kinetic energy.

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#26 question

4vir4ik [10]

So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>

<h3>Introduction</h3>

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

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$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

<h3>Problem Solving</h3>

We know that :

h = height = 5.00 m
g = acceleration of the gravity = 1.6 m/s²

What was asked :

t = interval of the time = ... s

Step by step :

$\sf{t = \sqrt{\frac{2 \cdot h}{g}}}$

$\sf{t = \sqrt{\frac{2 \cdot 5}{1.6}}}$

$\sf{t = \sqrt{6.25}}$

$\boxed{\sf{t = 2.5 \: s}}$

<h3>Conclusion</h3>

So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.

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