<h3>Explanation</h3>
The angular momentum of a rolling body is the product of the body's moment of inertia and its angular velocity.
where
- is the angular momentum of a rolling body;
- is the body's moment of inertia; And
- is the body's angular moment.
What's the moment of inertia of this bowling ball?
Assuming that the ball is a solid sphere. For a solid sphere,
.
where
- is the moment of inertia of the sphere;
- is the mass of the sphere; and
- is the radius of the sphere.
for this sphere. .
What's the angular momentum of this bowling ball?
.
.
Answer:
an object remains at rest (or motion) unless acted upon by an outside force
Explanation:
force that created the moon imparted velocity which was restrained by the gravitational pull of the earth
Answer: 42 N-s
Explanation: The area under the curve is equal to the impulse, so you take the area of the two triangles and add it to the area of the rectangle.
Area of a triangle: 1/2bh
Area of a rectangle: bxh
2(1/2x2x7)=14+(4x7)=42 N-s
I think it is b because atoms make up molecules...
hope it helps:)
Answer:
if you need an actual number answer you can use :Vf = Vi + at. If you throw the ball it will have an initial force beside gravity accelerating the fall temporarily from greater than throw it downwards, its acceleration (in the absence of air resistance) will be greater than 9.8 m/s2 until it slows back down to a constant 9.8 m/s2 after ( t )amount of time
Explanation:
If you drop a ball, it accelerates downward at 9.8 m/s2. if instead you throw the ball straight downwards While throwing, we apply an additional force other than the gravitational force.
This gives an additional, temporary acceleration along with the gravitational acceleration.
Thus from the instant it is thrown and the instant it leaves your hand, the object is under variable acceleration, the variation of acceleration being the reason of the varying force which we do apply on the object. But once it leaves our hand it is always under constant acceleration of g which is9.8 m/s2