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Pani-rosa [81]
3 years ago
11

A rock is dropped from a bridge to the water below. It takes 3.2 s for the rock to hit the water. Find the speed (in m/s) of the

rock as it hits the water. How high (in m) is the bridge above the water
Physics
1 answer:
Eduardwww [97]3 years ago
8 0
Kinematic equations 
v=at. v=9.81x3.2 v=32m/s (approx)
v^2=2axheight.
32x32/2x10=height
16x32/10 = height
height is approx 48metres
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Answer: Your answer is<u> 1.36.</u>

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5 0
3 years ago
2. The water is then heated to its boiling point. Calculate the specific latent heat of
Law Incorporation [45]

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

Q=m\lambda_v

where

m is the mass of the water sample

\lambda_v is the specific latent heat of vaporization of water

In this problem, we know

Q=813,600 J

m = 330 g

Solving the equation for \lambda_v, we find

\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g

6 0
4 years ago
A wire carrying a 32.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's
marin [14]

Answer:

2.24 T

Explanation:

From Electromagnetic Field,

F = BILsin∅................ Equation 1

Where F = Force on the wire, B = Field strength, I = current flowing in the conductor, L = length of the conductor, ∅ = The angle the conductor makes with the magnetic field.

Making B the subject of the equation,

B = F/ILsin∅..................... Equation 2

Given: F = 2.15 N, I = 32 A, L = 3.00 cm = 0.03 m, ∅ = 90° ( the wire is perpendicular to the magnetic field)

Substitute into equation 2

B = 2.15/(32×0.03×sin90°)

B = 2.15/0.96

B = 2.24 T.

Hence the Field strength = 2.24 T

7 0
4 years ago
Determine the distance from the Earth's center to a point outside the Earth where the gravitational acceleration due to the Eart
Temka [501]

The distance from the Earth's center to the point outside the Earth is 55800 Km

<h3>How to determine the distance from the surface of the Earth</h3>
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  • Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
  • Mass of the Earth (M) = 5.97×10²⁴ Kg
  • Distance from the surface of the Earth (r) =?

g = GM / r²

Cross multiply

GM = gr²

Divide both sides by g

r² = GM / g

Take the square root of both sides

r = √(GM / g)

r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]

r = 4.94×10⁷ m

Divide by 1000 to express in Km

r = 4.94×10⁷ / 1000

r = 4.94×10⁴ Km

<h3>How to determine the distance from the center of the Earth</h3>
  • Distance from the surface of the Earth (r) = 4.94×10⁴ Km
  • Radius of the Earth (R) = 6400 Km
  • Distance from the centre of the Earth =?

Distance from the centre of the Earth = R + r

Distance from the centre of the Earth = 6400 + 4.94×10⁴

Distance from the centre of the Earth = 55800 Km

Learn more about gravitational force:

brainly.com/question/21500344

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5 0
2 years ago
The driving force behind the formation of the solar system and planets is called
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I think it is high pressure / gravity and high temperatures
6 0
3 years ago
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