1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Evgen [1.6K]
3 years ago
13

Electrical equipment is required to be adequately protected against short-circuit current conditions per NEC 110.10 and several

other complementary NEC requirements. OSHA requires equipment short-circuit current protection in 1910.303(B)(viii)(5).
Physics
1 answer:
Anna11 [10]3 years ago
8 0

ANSWER:

The statment is true.

STEP-BY-STEP EXPLANATION:

Per Osha 1910.303 b (5):

The overcurrent protective devices, the total impedance, the component short-circuit current ratings, and other characteristics of the circuit to be protected shall be selected and coordinated to permit the circuit protective devices used to clear a fault to do so without the occurrence of extensive damage to the electrical components of the circuit. This fault shall be assumed to be either between two or more of the circuit conductors, or between any circuit conductor and the grounding conductor or enclosing metal raceway.

You might be interested in
A mouse jumps horizontally from a box of height 0.25m.  If the mouse jumps with a speed of 2.1 m/s, how far from the box does th
Sladkaya [172]

The mouse would land 0.47 m away from the box.

3 0
3 years ago
Read 2 more answers
Consider the following mass distribution where the x- and y-coordinates are given in meters: 5.0 kg at (0.0, 0.0) m, 2.9 kg at (
Sauron [17]

Answer:

x = -1.20 m

y = -1.12 m

Explanation:

as we know that four masses and their position is given as

5.0 kg (0, 0)

2.9 kg (0, 3.2)

4 kg (2.5, 0)

8.3 kg (x, y)

As we know that the formula of center of gravity is given as

x_{cm} = \frac{m_1 x_1 + m_2x_2 + m_3x_3 + m_4x_4}{m_1 + m_2 + m_3 + m_4}

0 = \frac{5(0) + 2.9(0) + 4(2.5) + 8.3 x}{5 + 2.9 + 4 + 8.3}

10 + 8.3 x = 0

x = -1.20 m

Similarly for y direction we have

y_{cm} = \frac{m_1 y_1 + m_2y_2 + m_3y_3 + m_4y_4}{m_1 + m_2 + m_3 + m_4}

0 = \frac{5(0) + 2.9(3.2) + 4(0) + 8.3 y}{5 + 2.9 + 4 + 8.3}

9.28 + 8.3 x = 0

x = -1.12 m

5 0
3 years ago
a cell phone uses 3.0V battery. the circuit board needs a 0.05 A current. what size resistor is needed to generate this current
san4es73 [151]

Answer:

60 Ohms

Explanation:

Ohms law states that the voltage in the circuit is directly proportional to the current through the circuit components and expressed as

V=IR

Where V is the voltage, I is current and R is resistance

Making R the subject of the formula then

R=\frac {V}{I}

Substituting 3.0V for V and 0.05 A for I then

R=\frac {3}{0.05}=60.0

Therefore, resistance is 60.0 Ohms

7 0
3 years ago
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
compare the theories that scientists proposed about the source of the sun's energy with the process of nuclear fusion in the sun
ANTONII [103]
The sun's source of energy is know as nuclear fusion (means to fuse) this process has a small nuclei atoms that join together to form a large nucleus. The result of this process is released energy. The fusion of hydrogen into helium in the sun makes a large amount of energy and this is known as the sun's energy source.
The theories that scientist proposed about the source of the sun's energy was that the sun burned fuel to generate its energy and that gravity was causing the sun to shrink slowly and have its energy released. Also both of these theories were disproved.
.
3 0
2 years ago
Other questions:
  • The picture on the left represents the reactants in the equation and the picture on the right represents the products. Does this
    9·1 answer
  • Boss tweed encourages his associates to work "like a well-oiled machine", thus providing his workers with
    10·2 answers
  • What momentum of a 50kilogram ice skater gliding across the ice at a speed of 5m/s?
    14·2 answers
  • A roller coaster starts at the top of a straight track that is inclined at 30degrees with the horizontal. This causes it to acce
    5·2 answers
  • A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete
    11·1 answer
  • When an object is stationary, all of the forces acting on it are balanced
    14·2 answers
  • A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial tempe
    6·1 answer
  • Hank eats many fatty foods. he doesn't exercise or wear sunscreen. hank is at risk for developing _____
    7·1 answer
  • Calculate the mass of a planet that exerts a 1.5 X 10 13 N force on a 5.4 x 10
    14·2 answers
  • Explain your problem of<br>Federalism<br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!