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Evgen [1.6K]
3 years ago
13

Electrical equipment is required to be adequately protected against short-circuit current conditions per NEC 110.10 and several

other complementary NEC requirements. OSHA requires equipment short-circuit current protection in 1910.303(B)(viii)(5).
Physics
1 answer:
Anna11 [10]3 years ago
8 0

ANSWER:

The statment is true.

STEP-BY-STEP EXPLANATION:

Per Osha 1910.303 b (5):

The overcurrent protective devices, the total impedance, the component short-circuit current ratings, and other characteristics of the circuit to be protected shall be selected and coordinated to permit the circuit protective devices used to clear a fault to do so without the occurrence of extensive damage to the electrical components of the circuit. This fault shall be assumed to be either between two or more of the circuit conductors, or between any circuit conductor and the grounding conductor or enclosing metal raceway.

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Kristina wants to paint the living room a bright blue. Maya prefers the dark blue paint. In other words, they disagree about the
Kruka [31]

Answer:

Intensity

Explanation:

Intensity basically means the amount of light. Hence, they are arguing about the amount of light that one color reflects more than another.

8 0
4 years ago
Read 2 more answers
A light source shines light consisting of two wavelengths, λ1 = 540 nm (green) and λ2 = 450 nm (blue), on two slits separated by
densk [106]

Answer:

The maximun distance is  z_1 = z_2 = 0.0138m

Explanation:

    From the question we are told that

       The wavelength are  \lambda _ 1 = 540nm  (green) = 540 *10^{-9}m

                                           \lambda_2 = 450nm(blue) = 450 *10^{-9}m

        The distance of seperation of the two slit is d = 0.180mm = 0.180 *10^{-3}m

        The distance from the screen is D = 1.53m

Generally the distance of the bright fringe to the center of the screen is mathematically represented as

           z = \frac{m \lambda D}{d}

   Where m is  the order of the fringe

For the first wavelength  we have

        z_1 = \frac{m_1 (549 *10^{-9} * (1.53))}{0.180*10^{-3}}

             z_1=0.00459m_1 m

                 z_1= 4.6*10^{-3}m_1 m ----(1)

For the second  wavelength  we have              

        z_2 = m_2 \frac{450*10^{-9} * 1.53 }{0.180*10^{-3}}

        z_2 = 0.003825m_2

        z_2 = 3.825 *10^{-3} m_2 m  ----(2)

From the question we are told that the two sides coincides with one another so

            zy_1 =z_2

         4.6*10^{-3}m_1 m = 3.825 *10^{-3} m_2 m

          \frac{m_1}{m_2}  = \frac{3.825 *10^{-3}}{4.6*10^{-3}}

Hence for this equation to be solved

       m_1 = 3

and  m_2 = 4

Substituting this into the  equation

                      z_1 = z_2 = 3 * 4.6*10^{-3} = 4* 3.825*10^{-3}

      Hence z_1 = z_2 = 0.0138m

                       

7 0
3 years ago
What is the metric unit for distance?
Gemiola [76]

Answer:

meters

Explanation:

4 0
4 years ago
What is the force needed to change a cyclist's momentum by 24kg m/s in 4 seconds?
zloy xaker [14]
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3 0
3 years ago
Dust and gas are pulled together by the force known as what?​
olga nikolaevna [1]

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