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ioda
3 years ago
14

True or false if a radius of a circle intersects a chord it is perpendicular to that chord

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0
It would be false





*Character limit fill ignore*
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A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s
quester [9]

Answer:

a) P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

b) p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

c) L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

d) L_q =\frac{20^2}{30(30-20)}=1.333 people

e) W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

f) W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

p_x represent the probability that the employee is busy

L_s represent the average number of people receiving and waiting to receive some information

L_q represent the average number of people waiting in line to get some information

W_s represent the average time a person seeking information spends in the system

W_q represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}

And in order to find the probability we can do this:

P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33 and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

L_s= \frac{\lambda}{\lambda -\mu}

And replacing we got:

L_s =\frac{20}{30-20}=\frac{20}{10}=2 people

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}

And replacing we got this:

L_q =\frac{20^2}{30(30-20)}=1.333 people

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours

6 0
3 years ago
Read 2 more answers
Fill in the blank:
sp2606 [1]
<span>I can be wrong, but I think that the answer is: To find the values of p, q, r and s, you should start by finding all factor pairs of the leading coefficiant and constant term. </span>
4 0
3 years ago
It took Mrs. Johnson 1/2 an hour to walk 2 1/2 miles. What is her speed in miles per hour?​
Arisa [49]

Answer:

I think its 5 mph

Step-by-step explanation:

3 0
4 years ago
A circular plate has a diameter of 6 inches. What is the exact area of the plate? A. 3π square inches B. 9π square inches C. 6π
Naddika [18.5K]
Hello 

A will be your answer.


Hope this helps!
7 0
3 years ago
Answers for the 2 boxes please:)​
masha68 [24]

Answer:

(5,-5)

Step-by-step explanation:

<u>Eliminate</u><u> </u><u>y-term</u>

(2x + 5x) + ( - 3y + 3y) = 25 + 10 \\ 7x = 35 \\ x =  \frac{35}{7}  \\  x = 5

We can eliminate x-term but for this system of equations, eliminating y-term is faster.

<u>Substitute</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>given</u><u> </u><u>equations</u><u>.</u>

I will choose to substitute in the first equation.

2x - 3y = 25 \\ 2(5) - 3y = 25 \\ 10 - 3y = 25 \\ 10 - 25 = 3y \\  - 1 5 = 3y \\ 3y  =  - 15 \\ y =  - 5

<u>Answer</u><u> </u><u>Check</u>

Substitute both x-value and y-value in any given equations

2x - 3y = 25 \\ 2(5) - 3( - 5) = 25 \\ 10 + 15 = 25 \\ 25 = 25

The equation is true. (<em>It</em><em> </em><em>is</em><em> </em><em>better</em><em> </em><em>to</em><em> </em><em>check</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>for</em><em> </em><em>both</em><em> </em>equation.)

Thus the answer is (5,-5)

6 0
3 years ago
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