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dimaraw [331]
3 years ago
10

What is the value of x?

Mathematics
1 answer:
Reika [66]3 years ago
7 0
The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides
VT/TK = VY/YK
95.2/168 = 34/YK
YK = (168·34)/95.2 = 60 cm
x = VY + YK = 34 + 60 = 94 cm

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What is the solution to the system below? <br> y = -3x - 2<br> 6x + 2y = -4
Alja [10]

Answer:

Infinitely many solutions

Step-by-step explanation:

Since y=-3x-2, plug it in (2)

6x+2(-3x-2)=-4.

Distribute:

6x-6x-4=-4

-4=-4

Infinetly many solutions.

Hope this helps :)

4 0
3 years ago
Please Help Me!!! 98 Points for Brainliest!!
Savatey [412]

vertical asymptote at x = 2 and x = - 2

horizontal asymptote at y = 2

the function → ±  ∞ at x = 2 and x = - 2 ⇒ vertical asymptotes

As x → ± ∞, y → -2 ⇒ y = -2 is a horizontal asymptote



6 0
3 years ago
Read 2 more answers
A. 60°
Tju [1.3M]

Answer:

60° is the value of y....

7 0
2 years ago
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Equation of the line (-6,5) and (8,14) in standard form
blsea [12.9K]

Answer:

\huge\boxed{9x-14y=-70}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, 5) and (8, 14).

Substitute:

m=\dfrac{14-5}{8-(-6)}=\dfrac{9}{14}\\\\y-5=\dfrac{9}{14}(x-(-6))\\\\y-5=\dfrac{9}{14}(x+6)

Thew standard form of an equation of a line:

Ax+By=C

transform:

y-5=\dfrac{9}{14}(x+6)\qquad|\text{multiply both sides by 14}\\\\14y-14\cdot5=14\!\!\!\!\!\diagup^1\cdot\dfrac{9}{14\!\!\!\!\!\diagup_1}(x+6)\\\\14y-70=9(x+6)\\\\14y-70=9x+54\qquad|\text{subtract}\ 9x\ \text{from both sides}\\\\-9x+14y-70=54\qquad|\text{add 70 to both sides}\\\\-9x+14y=70\qquad|\text{change the signs}\\\\9x-14y=-70

4 0
3 years ago
Find the angle 0 between the vectors. u=(1, 1, 1, 0), v = (4, 4, 4, 4).
Naya [18.7K]

Answer:

30 degrees

Step-by-step explanation:

u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12

|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)

|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8

cos(theta)=u dot v/(|u||v|)

cos(theta)=12/(sqrt(3)*8)

cos(theta)=3/(sqrt(3)*2)

cos(theta)=sqrt(3)/2

theta=30 degrees

6 0
3 years ago
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