Refusal to submit to the required test to determine the alcohol/drug contentof any person operating a motor vehicle will result
1 answer:
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Answer:
The answer is B- 12
Explanation:
The glycolysis of one glucose molecule produces two acetyl CoA molecules, the reactions in the glycolytic pathway and citric acid cycle produce six CO2 molecules, ten (10) NADH molecules, and two (2) FADH2 molecules per glucose molecule. Therefore the total number of NADH + FADH2 molecules produced is 12.
Answer:
B) 1 black eyes, green skin, two eyes : 1 black eyes, green skin, one eye : 1 black eyes, white skin, two eyes : 1 orange eyes, green skin, two eyes : 1 orange eyes, white skin, two eyes : 1 orange eyes, white skin, one eye
Explanation:
Parentals: BbGgCc x bbggcc
The punette square diagram of the cross of these two parents is attached.
B = black eyes, b = orange eyes;
G = green skin, g = white skin;
C = two eyes, c = one eye
Progeny with BbGgCc genotype → black eyes, green skin, two eyes = 8
Progeny with BbGgcc genotype → black eyes, green skin, one eye = 8
Progeny with BbggCc genotype → black eyes, white skin, two eyes = 8
Progeny with bbGgCc genotype → orange eyes, green skin, two eyes = 8
Progeny with Bbggcc genotype → black eyes, white skin, one eye = 8
Progeny with bbGgcc genotype → orange eyes, green skin, one eye = 8
Progeny with bbggCc genotype → orange eyes, white skin, two eyes = 8
Progeny with bbggcc genotype → orange eyes, white skin, one eye = 8
So, if we will see them in the form of ratio then each of the genotype will be in the ratio of 1 i.e. black eyes, green skin, two eyes: black eyes, green skin, one eye: black eyes, white skin, two eyes: orange eyes, green skin, two eyes: black eyes, white skin, one eye: orange eyes, green skin, one eye: orange eyes, white skin, two eyes : orange eyes, white skin, one eye = 1:1:1:1:1:1:1:1.
So, in view of above option B is most appropriate.
Note: In a trihybrid cross, a total of 64 progeny types may be produced.
