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3 years ago

How do you draw and number line and graph with -5 and -(-5) on it

Mathematics

2 answers:

NARA [144]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

Draw a line with points on it from -10 to 10 going by 1

Put a dot at -5 for the -5 point

-(-5) is 5

Put a dot at 5

Lilit [14]3 years ago

4 0

Answer:

You add -5, and the absolute value of -5 is 5, so you add 5 also.

Step-by-step explanation:

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What is the answer to the variable x in the multi-step problem 8x-6=2x-6+6x

nasty-shy [4]

Answer:

All real numbers are solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

8x−6=2x−6+6x

Step 1: Simplify both sides of the equation.

8x−6=2x−6+6x

8x+−6=2x+−6+6x

8x−6=(2x+6x)+(−6)(Combine Like Terms)

8x−6=8x+−6

8x−6=8x−6

Step 2: Subtract 8x from both sides.

8x−6−8x=8x−6−8x

−6=−6

Step 3: Add 6 to both sides.

−6+6=−6+6

0=0

5 0

3 years ago

Section J in an arena has 20 rows each row has 15 seats all tickets cost $18 each if all the seats are sold, how much money will

quester [9]

If there are 20 rows each and 15 per row then you would multiply 20(15) = 300 then so there are 300 seats in Section J. each seat is 18$ so you would multiply 300(18) = 5400 so section J would get 5,400$ if it were to be sold out. The equation is 20(15)=300(18)=5400

5 0

3 years ago

45% to a decimal ples help out

yan [13]

Answer:

45% = 0.45

Step-by-step explanation:

45%

= $\frac{45}{100}$

= 0.45

7 0

3 years ago

Read 2 more answers

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4=dcba. The digits a, b,

Arisa [49]

The given is that A B C D x 4 = D C B A

Possible values of A are 1 or 2. It can't be 1 since the final result A is in unit place and 1 is not possible when we multiply any number by 4

2 B C D x 4 = D C B 2
It is clear above, that D = 8
2 B C 8 x 4 = 8 C B 2
Possible values of B should be 1 or 2
We try B=1

2 1 C 8 x 4 = 8 C 1 2

To find for C, you can use the equation:

(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,

C = 7
So, the number is 2178.

5 0

3 years ago

Read 2 more answers