So average is of the first 6 tests is 82 well that means
(test1 + test2+ test3+ test4 + test5+test6)/6 = 82
so now let do some cross multiplliying
test1 + test2 + test3 + test 4 + test5 +test6 = 82*6
test1 + test2 + test3 + test 4 + test5 +test6 = 492
now lets see if we can find that 7th test score
(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5
So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.
(492 + test7 )/7 = 80.5
test7 = (80.5*7)-492 = 71.5
Answer:
I believe it is a=64; b=2 divided by 10 (I'm sorry if it's wrong I hope you pass)
Step-by-step explanation:
The quadratic equation is x² + (p - 5)x + 2q = 0.
By Vieta's Formula,
we have SOR = -b/a and POR = c/a.
=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.
=> 3 = 5 - p and -18 = 2q
Hence, p = 2 and q = -9.
Alternate Method:
We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.
=> (x + 3)(x - 6) = x² - 3x - 18.
By Comparing Coefficients,
(p - 5) = -3 and 2q = 18.
Hence p = 2 and q = -9.
