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bekas [8.4K]
2 years ago
9

Anyone Great at math? Here you go!

Mathematics
1 answer:
Arisa [49]2 years ago
6 0

the blue dotted line means the parent function was shifted 2 units down

 so the graph is g(x) = (1/3)^x-2


Answer would be A.

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HELP PLEASE MY WORK HAS TO BE DUE IN A FEW MINUTES PLEASE HELP
PilotLPTM [1.2K]

Given: 2/3 every 30 seconds

If we cut 2/3 in half, we get 1/3. This would also mean we cut the time in half 30 / 2 = 15 seconds

Therefore, 1/3 of the length every 15 seconds.

15 + 15 + 15 = 45 seconds to go the full length of the path

3 0
2 years ago
I need help ! What's 2+2-8^2+208
Nata [24]

Answer:

148

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A right triangle ABC is shown. Leg AC has length 18, leg BC has length 24, and hypotenuse AB has length 30. Find the exact value
Tresset [83]
Although there i no triangle given as the question requires, I am still going to answer because I understand it.

ABC is a right angled triangle. The triangle is 90° at C.

The trigonometric ratio sine is given by, sine = opposite/hypotenuse .
Cosine = adjacent/hypotenuse
 
So therefore, Sin A = 24/30
                               = 4/5

                     Cos A = 18/30
                               = 3/5
8 0
2 years ago
Read 2 more answers
Bill weighs 150 lbs. He wants to gain 2 lbs per week for football season. Jamal runs track. He wants to lose weight so he can ru
mars1129 [50]

The <u><em>correct answer</em></u> is:

15 weeks

Explanation:

Let w be the number of weeks.  Bill weighs 150 pounds and wants to gain 2 lbs per week; this gives us the expression 150+2w for Bill.

Jamal weighs 195 and wants to lose 1 pound per week; this gives us the expression 195-1w for Jamal.

To determine how many weeks it will take them to weigh the same, we set the two expressions equal:

150+2w=195-1w

Add 1w to each side:

150+2w+1w = 195-1w+1w

150+3w = 195

Subtract 150 from each side:

150+3w-150 = 195-150

3w = 45

Divide each side by 3:

3w/3 = 45/3

w = 15

7 0
3 years ago
Read 2 more answers
What is the easiest way to solve a quadratic equation?​
algol [13]

Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
2 years ago
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