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2 years ago

Ok serous question this has nothing to do with my other questions would you guys care if I committed ya know

Mathematics

2 answers:

Pani-rosa [81]2 years ago

5 0

Answer:

I don't know you but I care. I am always here to talk. For real I don't have a life. Lol

Step-by-step explanation:

lys-0071 [83]2 years ago

5 0

Yes we would care, and please don’t do it. I know life right now is not that great, but don’t do it. Your family is going to be sad, and they are going to be going through a lot of pain. Plus life of amazing and we need to cherish every moment we have left.

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The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1

Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

$\frac{dr}{dt}=7\ mm/hr$

Volume of cylinder is given by:

$V=\pi\ r^2h$

Finding derivative of the Volume with respect to time.

$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

Plugging in the values given:

$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

$\frac{dV}{dt}=252\pi$

Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

$\frac{dV}{dt}=791.28\ mm^3/hr$ (Answer)

Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

6 0

2 years ago

Find the first four terms of the sequence given by the following.<br> an=51 + (n-1).8, n=1, 2, 3...

pav-90 [236]

Answer:

Step-by-step explanation:

a1 = 51 + (1 -1 ) * 0.8

a1 = 51

a2 = 51 + (2 - 1)*0.8

a2 = 51 + 0.8

a2 = 51.8

a3 = 51 + (3 - 1)*0.8

a3 = 51 + 2*0.8

a3 = 51 + 1.6

a3 = 52.6

a4 = 51 + (4 - 1)*0.8

a4 = 51 + 2.4

a4 = 53.4

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2 years ago

What are all the possible cross sections of a cone

natita [175]

Answer:

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Step-by-step explanation:

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2 years ago

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How to solve Piecewise function- tax problem?

Nimfa-mama [501]

Answer:idk I’m just a little kid

Step-by-step explanation:

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3 years ago

1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

2 years ago