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malfutka [58]
3 years ago
5

Can somebody help me with my packet please :D

Mathematics
1 answer:
Aleks [24]3 years ago
7 0

Answer:

Number 1 = 5        Number 2 = 13/12 or 1 and 1/12

Step-by-step explanation:

The properties of triangles states that the third side is no less than the difference between the other 2 sides. So we can subtract B from A in number 1 to get 5. In number 2, we need to convert them both into twelfths in order to find the difference, 2/3 is 8/12 and 1 3/4 = 7/4.  7/4 in twelfths is 21/12. Now we subtract and ignore the denominators, 21 - 8 is 13. You now have 13/12 for number 2.

Hope this helps.

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]

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Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

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4 years ago
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Answer:

20

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