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Inessa [10]
3 years ago
10

Please Help Me With This Math Problem

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

Yes the relationship is linear and given by:

y+2=-\frac{5}{4} \,(x+9) (first option of your list)

Step-by-step explanation:

Yes, it is a linear expression. As we did in previous exercises, we calculate the difference between consecutive y values of the table, and write down the answers we get:

-7-(-2) = -7+2 = -5

-12-(-7) = -12 +7 = -5

-17 - (-12) = -17 + 12 = -5

We notice that all of them give "-5"

Now we evaluate the difference between consecutive x-values in a similar fashion:

-5 -(-9) = -5+9 = 4

-1-(-5) = -1+5 = 4

3-(-1) = 3+1 = 4

We see that they all give 4 as the difference.

That means that the rate of change \frac{y_2-y_1}{x_2-x_1} =\frac{y_3-y_2}{x_3-x_2}=\frac{y_4-y_3}{x_4-x_3}=\frac{-5}{4}

This means that the slope (rate of change) of the line is "-5/4"

We can now use the general point-slope form to write the equation of the line, using the first pair of the table as our selected point, and using "-5/4" for the slope:

y-y_0=m\,(x-x_0)\\y-(-2)=-\frac{5}{4} \,(x-(-9))\\y+2=-\frac{5}{4} \,(x+9)

which is the first expression listed among your possible answer choices.

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Convert
ICE Princess25 [194]

Answer:

The correct option is A.

Step-by-step explanation:

The given number is

\frac{5}{11}

Where 5 is dividend and 11 is divisor.

Since dividend is less than divisor we add a decimal place and the first zero. Notice the decimal point which has appeared on the answer line and by the dividend. It does not appear anywhere else.

Now the dividend is 50. Divide the number by divisor.

11\times 4=44

Subtract 44 from 50.

50-44=6

Therefore remainder is 6. Place a zero after 6.

Now the new dividend is 60. Divide the number by divisor.

11\times 5=55

Subtract 55 from 60.

60-55=5

Therefore remainder is 5.

\frac{5}{11}=0.454545

\frac{5}{11}\approx 0.45

Therefore option A is correct.

5 0
3 years ago
A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc
Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)

\implies y_{\rm max}=57\,\mathrm m

b. The ball's height in the air y at time t is given according to

y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2

Solve for t when y=0:

17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s

3 0
3 years ago
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