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Molodets [167]
3 years ago
14

How can use base- ten blocks to find 2.16 divided by 3?

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0
Youll have to move the decimal to the right twise on both of then them divide normally
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Diagram 1 shows absolute function of f(x)= 3x-1a)State the domain for that functionb)State the value of a
omeli [17]

The function given is,

f(x)=3x-1

a) Domain

This is the set of all points over which a function is defined.

Therefore, the domain of the function is

-2\leq x\leq1

b) Solving for the value of a

To solve for the value of a, the value of y = 0 at x = a

Therefore,

\begin{gathered} f(x)=3x-1 \\ \text{where,} \\ f(x)=y=0 \\ x=a \end{gathered}

Solving for a

\begin{gathered} 0=3(a)-1 \\ 0=3a-1 \\  \end{gathered}

Collect like terms

\begin{gathered} 3a=0+1 \\ 3a=1 \end{gathered}

Divide both sides by 3

\begin{gathered} \frac{3a}{3}=\frac{1}{3} \\ a=\frac{1}{3} \end{gathered}

Hence,

a=\frac{1}{3}

3 0
1 year ago
Pls help me I’m struggling
konstantin123 [22]

Answer:2

Step-by-step explanation:

4 0
2 years ago
What is the y-intercept of the graph of y = 2.5'?
Paha777 [63]

Answer:

a. 2.5..... I believe but you should get other answers

4 0
2 years ago
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
What equation represents the relationship between p and q shown in the table
mash [69]

q = 10p because all of them are multiplied by ten

6 0
2 years ago
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