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fiasKO [112]
3 years ago
15

Simplify: (7x^2 − 8x − 4) + (−2x^2 + 3x + 5) + (5x^2 − 10x − 8)

Mathematics
1 answer:
kramer3 years ago
5 0
Step 1. Simplify
7x^2 - 8x - 4 - 2x^2 + 3x + 5 + 5x^2 - 10x - 8
Step 2. Collect like terms
(7x^2 - 2x^2 + 5x^2) + (-8x + 3x - 10x) + (-4 + 5 - 8)
Step 3. Simplify 

10x^2 - 15x - 7
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Which of the following is a solution of x^2 2x = −2?
dem82 [27]
x^2+2x=-2\\
x^2+2x+1=-1\\
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3 years ago
What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your
LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

y=27-x^2

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=27-x^2.

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

Area=Length\times width

Area=2x\times y

Substitute the value of y from the given equation.

Area=2x(27-x^2)

A=54x-2x^3      .... (1)

Differentiate with respect to x.

\frac{dA}{dx}=54-6x^2

Equate \frac{dA}{dx}=0, to find the critical points.

0=54-6x^2

6x^2=54

Divide both sides by 6.

x^2=9

x=\pm 3

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

A=54(3)-2(3)^3

A=162-54

A=108

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

7 0
3 years ago
Answer this question please and thank you
ELEN [110]

Answer:

x = -11

-11-3=-14

-14/7=-2

7 0
3 years ago
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