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4 years ago

Find the value of x if B is between A and C, AB=4x-9, BC= 3x+ 5, and AC=7

1 answer:

4 0

AB = 4 x - 9
BC = 3 x + 5
AC = 7

B is in between A and C. <u>So AB + BC = AC</u>

4x - 9 + 3 x + 5 = 7
7 x - 4 = 7 take -4 from LHS to the R H S (right hand side) it becomes +4
7 x = 7 + 4 = 11
x = 11/7 = 1.571

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4(5f + 9)

Marina86 [1]

Answer: hopes this helps i spent a lot of time on it !!!:)lol

2 0 + 3 6

− 8 − 1 2

2 0 + 1 0

1 0 ℎ − 1 5

− 1 2 − 1 4

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8 − 1 8

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

3(2x+5)=36<br>what is the value of x

Bond [772]

$3(2x+5)=36\\
6x+15=36\\
6x=21\\
x=\frac{21}{6}$

6 0

3 years ago

Please help I have no clue how to do this

Alinara [238K]

Step-by-step explanation:

It's a question of trigonometry.

You need to remember that tangent (tan) stands for Perpendicular / Base.

So, tan P = QR / PR

By Pythagoras Theorem,

34² = 30² + x²

x² = 34² - 30²

x² = 1156 - 900

x² = 256

x = 16

Now, placing the values,

tan P = 30 / 16

tan P = 1.875

HOPE IT HELPS ^_^

5 0

3 years ago

Hi! Pls help me with this question:

zimovet [89]

Answer:

PR=8

ST=5

Step-by-step explanation:

2x=8

x=4

PR=2x=8

5z=2z+3

3z=3

z=1

ST=5z=5

8 0

3 years ago

A license plate is to consist of 5 digits followed by 5 uppercase letters. Determine the number of different license plates poss

EastWind [94]

Answer:

$5.3044992\times 10^{10}$

Step-by-step explanation:

We are given that a license plate consist of 5 digits and 5 uppercase letters

Digits used=0,1,2,..9

Total number of letters=26

Repetition is not allowed

Total number of odd digits=(1,3,5,7,9)=5

The first place filled by 5

Second place filled by 4

Third place filled by 8

Fourth place filled by 7

Fifth place filled by 6

Sixth place filled by 26

Seventh place filled by 25

Eighth place filled by 24

Ninth place filled by 23

Tenth place filled by 22

Total number of possible different license plates = $5\times 4\times 8\times 7\times 6\times 26\times 25\times 24\times 23\times 22$ = $5.3044992\times 10^{10}$

7 0

3 years ago