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3 years ago

Find the value of x if B is between A and C, AB=4x-9, BC= 3x+ 5, and AC=7

1 answer:

4 0

AB = 4 x - 9
BC = 3 x + 5
AC = 7

B is in between A and C. <u>So AB + BC = AC</u>

4x - 9 + 3 x + 5 = 7
7 x - 4 = 7 take -4 from LHS to the R H S (right hand side) it becomes +4
7 x = 7 + 4 = 11
x = 11/7 = 1.571

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A square has side length (x+5) units. What is it’s area

daser333 [38]

The area of square is $x^{2}+10 x+25$ square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

$\text {Area of square }=\mathrm{a}^{2}$

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

$\text {Area of square }=(x+5)^{2}$

${\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}$

$\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}$

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3 years ago

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Gekata [30.6K]

Answer:

x = √6/2

Step-by-step explanation:

Side a = 1.73205 --> √3

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