Eggs with defects in terms of the number of eggs they inspected as shown
1 answer:
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Answer:
The correct answer is there are 3 cages and 4 tigers.
Step-by-step explanation:
Let there be x cages and y tigers.
According to the first condition, if we put one tiger in each cage, one tiger is left over.
∴ y - x =1
According to the second condition, if we put two tigers in each cage, one cage is left over.
∴ x - =1
⇒ 2x - y = 2
Therefore adding both the equations we get,
y - x + 2x - y = 2 + 1
⇒ x = 3
⇒ y = 4
Therefore there are 4 tigers and 3 cages.