To solve this problem you must apply the proccedure shown below:
1. You have that:
<span> - The scale model is 11 inches long and 8.5 inches wide.
- The door to her room takes up 1.75 inches.
- The longest wall in Jessica’s actual room is 15 feet long.
2. Therefore, the actual size of the door is:
15 feet=180 inches
1.75 inches(180 inches/11 inches)=28.63 inches
3. If the door in completely open, you must apply the formula for calculate the area of a semicircle:
A=</span>πr²/2
r=28.63 inches
A=π(28.63 inches)²/2
A=1288.11 inches²
The answer is: 1288.11 inches²
Answer:
6 inches
Step-by-step explanation:
The diameter of the burners are 6 inches because the diameter is twice the size of the radius.
Total tickets sold = 159
Total sales = $1100.60
Child admission = $5.20
Adult admission = $8.90
Assumed all 159 tickets are Child admission tickets
Total sales = 159 x 5.2 = $826.80
Difference in amount = $1100.60 - $826.80 = $273.80
The difference must be contributed by the Adult Admission Tickets, which has a difference of $8.90 - $5.20 = $3.70
$273.80 ÷ $3.70 = 74 adult tickets
159 - 74 = 85 child tickets
Given:
Big cone : diameter = 12 cm ; height = 18 cm ; base = 14 cm
Small cone: diameter = 12 cm ; height = 6 cm ; base = 14 cm
Volume of a cone-shaped container = π r² h/3
Big cone:
V = 3.14 * (6cm)² * 18cm/3
V = 3.14 * 36cm² * 6cm
<span>V = 678.24 cm³
</span>Small cone:
V = 3.14 * (6cm)² * 6cm/3
V = 3.14 * 36cm² * 2cm
<span>V = 226.08 cm³
</span>Big cone - small cone = volume of water
678.24 cm³ - 226.08 cm³ = 452.16 cm³