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3 years ago

10

A certain alloy contains 14.25% nickel. How much nickel is there in a piece weighing 375 pounds? Round your answer to the neares

t hundredth.
A. 78.92 pounds B. 12.24 pounds C. 112.49 pounds D. 53.44 pounds

1 answer:

Fed [463]3 years ago

5 0

D because 375 * .1425 = 53.44

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How would I change this to standard form. <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20x%20-%201"

Pie

Answer:

x - 2y = 2

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and A, B are integers )

given y = $\frac{1}{2}$ x - 1

multiply through by 2 to eliminate the fraction

2y = x - 2 ( subtract 2y from both sides )

0 = x - 2y - 2 ( add 2 to both sides )

x - 2y = 2 ← in standard form

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3 years ago

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

BartSMP [9]

Answer:

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 5.6 \ pounds/inch^2$

The sample size is n = 160

The sample mean is $\= x = 5.7 \ pounds/ inch^2$

The variance is $\sigma ^2 = 0.25$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu = 5.6$

The alternative hypothesis is $H_a : \mu > 5.6$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\sigma ^2 }$

=> $\sigma = \sqrt{0.25 }$

=> $\sigma = 0.5$

Generally the test statistics is mathematically represented as

$z = \frac{\= x - \mu }{ \frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{5.7 - 5.6 }{ \frac{0.5 }{\sqrt{ 160 } } }$

=> $z = 2.53$

From the z table the area under the normal curve to the left corresponding to 2.53 is

$p-value = P(Z > 2.53 ) =0.0057$

From the value obtained we see that the $p-value < \alpha$ hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that the believe that the valve performs above the specifications is true

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3 years ago

MATH: GRAPHS AND FUNCTIONS...HELP!

Maru [420]

Solution: Check the picture I uploaded.

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2 years ago

Given points A (-3,-4) and B (2,0), points P (-1,-12/5) partitions line AB in the ratio

kvv77 [185]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&A&(~ -3 &,& -4~) 
&P&(~ -1 &,& -\frac{12}{5}~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AP=\sqrt{[-1-(-3)]^2+[-\frac{12}{5}-(-4)]^2}
\\\\\\
AP=\sqrt{(-1+3)^2+(-\frac{12}{5}+4)^2}\implies AP=\sqrt{2^2+\left( \frac{8}{5} \right)^2}
\\\\\\
AP=\sqrt{4+\frac{64}{25}}\implies AP=\sqrt{\cfrac{164}{25}}\implies AP=\cfrac{\sqrt{164}}{\sqrt{25}}
\\\\\\
\boxed{AP=\cfrac{2\sqrt{41}}{5}}$

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&P&(~ -1 &,& -\frac{12}{5}~) 
&B&(~ 2 &,& 0~)
\end{array}
\\\\\\
PB=\sqrt{[2-(-1)]^2+[0-\left(-\frac{12}{5} \right)]^2}
\\\\\\
PB=\sqrt{(2+1)^2+\left( \frac{12}{5} \right)^2}\implies PB=\sqrt{9+\frac{144}{25}}\implies PB=\sqrt{\cfrac{369}{25}}
\\\\\\
PB=\cfrac{\sqrt{369}}{\sqrt{25}}\implies \boxed{PB=\cfrac{3\sqrt{41}}{5}}$

so, let's check the ratio of AP:PB

$\bf AP:PB\implies \cfrac{AP}{PB}\implies \cfrac{\frac{2\sqrt{41}}{5}}{\frac{3\sqrt{41}}{5}}\implies \cfrac{2\underline{\sqrt{41}}}{\underline{5}}\cdot \cfrac{\underline{5}}{3\underline{\sqrt{41}}}\implies \cfrac{2}{3}$

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3 years ago

Graphing Polynomial Functions

Mekhanik [1.2K]

Answer:

table and graph attached

Step-by-step explanation:

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3 years ago