Please Help I will give brainliest https://brainly.com/question/16655105

Delbert Rowell drove his tractor rig 58,125 miles in 6 months. Estimate how many miles he drove in each month

zzz [600]

Answer:

just do 58,125 divided by 6

Step-by-step explanation:

6 0

3 years ago

(18 + 7) x (11 - 7) write 3 steps then answer it and i will give u brainlyiest if u are correct

bezimeni [28]

Answer:

100

Step-by-step explanation:

(18 + 7) x (11 - 7)

25(11-7)

275-175

100

6 0

2 years ago

Read 2 more answers

3x – 2y = 17 –2x – 5y = 14 Solve using Elimination Please show work

OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

$3x- 2y = 17\\-2x -5y = 14$

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

$2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3$

Multiplying equation 2 by 3

$3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4$

Adding equation 3 and 4

$(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\$

Putting y = -4 in equation 1

$3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3$

Hence,

The solution is x=3 , y=-4 or (3,-4)

3 0

2 years ago

Mrs. Bonse bought a box of erasers. The box had 5 different shapes of erasers. There were 8 of each shape of eraser in the box.

JulsSmile [24]

Answer:

Gail is correct and Brianne is incorrect.

Step-by-step explanation:

If there are 5 different shaped erasers and 8 of each, you would have to multiply $5x8$ which equals 40. If there are 4 people in the group, 40 divided by 10 equals 4.

4 0

2 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

Given equation:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

1 year ago