So this first wants you to find where sin is √3/2 when θ is between π and 3π/2. θ would therefore be located at 2π/3.
Now plug in the value of θ for cosine:
cos (2π/3) = -1/2
And tangent:
tan (2π/3) = -√3/3
Answer:
<ABC = 15
< BAC = 150
Step-by-step explanation:
<C = <B since this is an isosceles triangle. We know this because AC = AB
<C = 15 so <ABC = 15
The sum of the angles of a triangle is 180
A + B+ C = 180
A + 15+15 = 180
A +30 =180
A = 180-30
A = 150
< BAC = 150
Answer: -8
Step-by-step explanation: When it says f(x), all you have to do is find value x on the coordinate plane and look up or down until you find a point that runs through that x value. In this case, if you draw a line on x=5, you can see that it goes across a point that has a y value of -8, which is your answer.
Answer:
x = 47°
Step-by-step explanation:
m∠DPB + ∠BPC = 180° (Definition of a straight line)
Plug in the corresponding numbers and variables to the corresponding places:
x + 133 = 180
Isolate the variable, x. Subtract 133 from both sides:
x + 133 (-133) = 180 (-133)
x = 180 - 133
x = 47
47° is your answer.
~
Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
<h3>
(See picture attached for sub-totals)
</h3>
a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%
