Answer:
The probability of finding a sample mean less than 18 hours is 0.0082
Step-by-step explanation:
To find the probability of finding a sample mean less than 18 hours, we need to calculate the z-score of this sample mean 18. And the probability of finding a sample mean less than 18 hours is P(z<z(18)).
Z-score can be calculated as follows:
z(18)=
where
- X is the sample mean (18 hours)
- M is the average hours dentists spend per week on fillings (20 hours)
- s is the standard deviation (10 hours)
- N is the sample size (144)
Putting the numbers, we get:
z(18)=
Using z- table we can find that P(z<z(18)) = 0.0082
8/100 * 125 =
(125 * 8)/100 =
1000/100 =
10
$125 + $10 = $135
Answer: B. $135.00
Answer: P(6/7G) = 729⁄16384 = 0.044
The probability of having exactly six seeds germinate is 0.044
Complete Question:
A certain seed has 75% germination rate. Of seven seeds are planted, find the probability of having exactly six seeds germinate.
Step-by-step explanation:
The probability that a seed will germinate is
P(G) = 0.75
The probability that a seed will not germinate is
P(G') = 1-0.75 = 0.25
Therefore the probability that only 6 will germinate can be written as;
P(6/7G) = the probability that 6 seed germinate × the probability that one seed will not geminate
P(6/7G ) =[ P(G)]^6 ×[ P(G')]
P(6/7G) = 0.75^6 × 0.25
P(6/7G) = 729⁄16384 = 0.044
Answer:
100
Step-by-step explanation:
