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Mademuasel [1]
2 years ago
13

100 Points!!!

Mathematics
2 answers:
Mars2501 [29]2 years ago
7 0

Let's see

#a

Take 28

  • (28)²
  • (30-2)²
  • 30²-2(30)(2)+2²
  • 900-120+4
  • 780+4
  • 784

#2

Take 9,10

  • 9³+10³
  • (9+10)(9²-9×10+10²)
  • (19)(81-90+100)
  • 19(181-90)
  • 19(91)
  • 1729
oee [108]2 years ago
4 0

Answer:

Two-digit number greater than 25:   32

Rewrite 32 as the difference of 2 numbers: 40 - 8

Therefore, x = 40  and  y = 8

\begin{aligned}\implies (40-8)^2 & =40^2-2(40)(8)+8^2\\ & = (4 \cdot 10)^2-(80)(8)+64\\ & = 4^2 \cdot 10^2-640+64\\ & = 16 \cdot 100-640+64\\ & = 1600-640+64\\ & = 960+64\\ & = 1024\end{aligned}

Let a = 10

Let b = 11

\begin{aligned}\implies 10^3+11^3 & =(10+11)(10^2-10 \cdot 11+11^2)\\& = 21(100-110+121)\\ & = 21(-10+121)\\ & = 21(111)\\& = 21 (100 + 10 + 1)\\ & = (21 \cdot 100)+(21 \cdot 10)+(21 \cdot 1)\\ & = 2100 +210+21\\ & = 2310 + 21\\ & = 2331\end{aligned}

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liberstina [14]

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mart [117]

»»————- ★ ————-««

I believe your answer is:  

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»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Solving for 'c'...}}}\\\\j = uc  \\------------\\\rightarrow \frac{j=uc}{u}\\\\\rightarrow \frac{j}{u}=c\\\\\rightarrow \boxed{c=\frac{j}{u}}}; u\neq 0

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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