This is an exponential function : f ( x ) = 2 · 5 ^x
The curve goes trough the points: ( 1, 10 ), ( 2, 50 ), ( 3, 250 ).
The multiplicative rate of change:
( 50 : 10 ) / ( 2 - 1 ) = 5 / 1 = 5
( 250 : 50 ) / ( 3 - 2 ) = 5 / 1 = 5
Answer: 5
The domain of the function will therefore be 0≤x<∞
<h3>Domain of a function</h3>
Domain of a function are the independent value for which a function exists. Given the function below;
f(x) = ![\sqrt[4]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D)
Since the value in the root cannot be negative hence the domain of the function will be all positive real numbers.
The domain of the function will therefore be 0≤x<∞
Learn more on domain here: brainly.com/question/25959059
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It is a very simple question to answer.
Obviously first we can calculate his weekly earnings and then multiply them by 4 to calculate his total earnings over the course of 4 year period.
So as he makes 6.2$ an hour. He will make 6.2 * 30 = 186 $ a week as that is the number of hours he works in a week.
Now we can multiply this by 4 to calculate his over all earnings. So 186 * 4 = 744.
Answer:
![A = 1172.965\,cm^{2}](https://tex.z-dn.net/?f=A%20%3D%201172.965%5C%2Ccm%5E%7B2%7D)
Step-by-step explanation:
Let be a side of 12 cm (l) and an apothem of 19 cm (p). First, the number of sides has to be determined:
![n =\frac{360^{\textdegree}}{2\cdot \tan^{-1}\left(\frac{6\,cm}{19\,cm} \right)}](https://tex.z-dn.net/?f=n%20%3D%5Cfrac%7B360%5E%7B%5Ctextdegree%7D%7D%7B2%5Ccdot%20%5Ctan%5E%7B-1%7D%5Cleft%28%5Cfrac%7B6%5C%2Ccm%7D%7B19%5C%2Ccm%7D%20%5Cright%29%7D)
![n = 10.271](https://tex.z-dn.net/?f=n%20%3D%2010.271)
The polygon has ten sides and the side length shall be re-adjusted:
![\theta = \frac{360^{\textdegree}}{10}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B360%5E%7B%5Ctextdegree%7D%7D%7B10%7D)
![\theta = 36^{\textdegree}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2036%5E%7B%5Ctextdegree%7D)
The side length is:
![l = 2\cdot (19\,cm)\cdot \tan 18^{\textdegree}](https://tex.z-dn.net/?f=l%20%3D%202%5Ccdot%20%2819%5C%2Ccm%29%5Ccdot%20%5Ctan%2018%5E%7B%5Ctextdegree%7D)
![l = 12.347\,cm](https://tex.z-dn.net/?f=l%20%3D%2012.347%5C%2Ccm)
The area of the polygon is:
![A = \frac{n\cdot l \cdot p}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bn%5Ccdot%20l%20%5Ccdot%20p%7D%7B2%7D)
![A = \frac{(10)\cdot (12.347\,cm)\cdot (19\,cm)}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%2810%29%5Ccdot%20%2812.347%5C%2Ccm%29%5Ccdot%20%2819%5C%2Ccm%29%7D%7B2%7D)
![A = 1172.965\,cm^{2}](https://tex.z-dn.net/?f=A%20%3D%201172.965%5C%2Ccm%5E%7B2%7D)