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AveGali [126]
3 years ago
5

Which ipv6 router message is sent via multicast with a scope of link-local with the expectation that all local routers will iden

tify themselves?
Computers and Technology
1 answer:
Artyom0805 [142]3 years ago
3 0
The Answer is Router <span> Solicitation. </span>
 This is because RS is used to determine which routers are present on a specific sub net by sending a message asking for a router advertisement that provides details about a specific router.
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Often, a single source does not contain the data needed to draw a conclusion. It may be necessary to combine data from a variety
nlexa [21]

To measure the pollution of a particular river, one must take the sample of the river and take the sample of pure water, then draw the conclusion, it will tell the amount of pollution in the river water.

<h3>What is pollution?</h3>

Pollution is the mixing of unwanted or harmful things in any substance or compound.

Water pollution is the mixing of toxics and chemicals in water.

Thus, to measure the pollution of a particular river, one must take the sample of the river and take the sample of pure water, then draw the conclusion, it will tell the amount of pollution in the river water.

Learn more about pollution

brainly.com/question/23857736

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6 0
2 years ago
The _____ row is typically the first row in a table.<br><br> banded<br> total<br> header<br> odd
rusak2 [61]

the first row of the table is know as the table header.

8 0
2 years ago
Read 2 more answers
Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th
Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

7 0
3 years ago
Task 1 – File Input
e-lub [12.9K]

Answer:

Check the explanation

Explanation:

using System;

using System.IO;

                 

public class Program

{

 

  public static void Main()

  {

      string[] lines;

      Console.WriteLine("enter name of the file");

      String fileName=Console.ReadLine();

     

      Console.WriteLine("enter path of the file");

      String filePath=Console.ReadLine();

     

      using (StreamReader streamReader = File.OpenText(filePath))

      {

          String text = streamReader.ReadToEnd();

          lines = File.ReadAllLines(filePath);

      }

      Console.WriteLine("Enter path of the file to write");

      String outputFilePath = Console.ReadLine();

      bool fileExist = File.Exists(outputFilePath);

      if (fileExist)

      {      

                  overWriteOrChangeFileName(outputFilePath);          

      }

      else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

      Console.Write("Input file Path"+filePath);

      Console.Write("output file path"+outputFilePath);

     

      void overWriteOrChangeFileName(String filePathtoCheck){

          Console.WriteLine("File exists. Do you want to overwrite the file or do you want to change the location and file name of the new file.Press Y to overwrite and press C to change the location and filename");

          String userInput=Console.ReadLine();

          if(userInput.Equals("Y")){

File.WriteAllLines(outputFilePath, lines);

          }else{

              Console.WriteLine("enter new path of the file including filename");

              String NewFileName=Console.ReadLine();

              outputFilePath=NewFileName;

              if(File.Exists(outputFilePath)){

                  overWriteOrChangeFileName(outputFilePath);                  

              }

              else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

          }

      }

  }

 

}

3 0
3 years ago
If a system's instruction set consists of an 8-bit opcode, what is the maximum number of output signal lines required for the co
otez555 [7]

Answer:

D. 256

Explanation:

Given

Instructions = 8\ bit

Required

Determine the maximum number of output

To get the required value, we make use of the following:

Maximum = 2^n

Where n is the bits of the opcode.

i.e.

n = 8

Substitute 8 for n in Maximum = 2^n

Maximum = 2^8

Maximum = 256

<em>Hence, option D answers the question</em>

6 0
3 years ago
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