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KonstantinChe [14]
3 years ago
5

Task 1 – File Input

Computers and Technology
1 answer:
e-lub [12.9K]3 years ago
3 0

Answer:

Check the explanation

Explanation:

using System;

using System.IO;

                 

public class Program

{

 

  public static void Main()

  {

      string[] lines;

      Console.WriteLine("enter name of the file");

      String fileName=Console.ReadLine();

     

      Console.WriteLine("enter path of the file");

      String filePath=Console.ReadLine();

     

      using (StreamReader streamReader = File.OpenText(filePath))

      {

          String text = streamReader.ReadToEnd();

          lines = File.ReadAllLines(filePath);

      }

      Console.WriteLine("Enter path of the file to write");

      String outputFilePath = Console.ReadLine();

      bool fileExist = File.Exists(outputFilePath);

      if (fileExist)

      {      

                  overWriteOrChangeFileName(outputFilePath);          

      }

      else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

      Console.Write("Input file Path"+filePath);

      Console.Write("output file path"+outputFilePath);

     

      void overWriteOrChangeFileName(String filePathtoCheck){

          Console.WriteLine("File exists. Do you want to overwrite the file or do you want to change the location and file name of the new file.Press Y to overwrite and press C to change the location and filename");

          String userInput=Console.ReadLine();

          if(userInput.Equals("Y")){

File.WriteAllLines(outputFilePath, lines);

          }else{

              Console.WriteLine("enter new path of the file including filename");

              String NewFileName=Console.ReadLine();

              outputFilePath=NewFileName;

              if(File.Exists(outputFilePath)){

                  overWriteOrChangeFileName(outputFilePath);                  

              }

              else

      {

          File.Create(outputFilePath);

          File.WriteAllLines(outputFilePath, lines);

      }

          }

      }

  }

 

}

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[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

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You have just performed a cpm analysis and have found that more than one path through the project network has zero slack values.
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Answer:

There are multiple critical paths

Explanation:

The critical path method (CPM), or critical path analysis (CPA), is an algorithm for scheduling a set of project activities. It is commonly used in conjunction with the program evaluation and review technique (PERT). A critical path is determined by identifying the longest stretch of dependent activities and measuring the time required to complete them from start to finish.

The essential technique for using CPM is to construct a model of the project that includes the following:

  •    A list of all activities required to complete the project (typically categorized within a work breakdown structure),
  •    The time (duration) that each activity will take to complete,
  •    The dependencies between the activities and,
  •    Logical end points such as milestones or deliverable items.      

Using these values, CPM calculates the longest path of planned activities to logical end points or to the end of the project, and the earliest and latest that each activity can start and finish without making the project longer. This process determines which activities are "critical" (i.e., on the longest path) and which have "total float" (i.e., can be delayed without making the project longer).

considering the above function of the cpm analysis because you have multiple path, there is tendency that more than path through the project network will have zero slack values.

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A technician is troubleshooting a Windows system in which an application works properly when the computer is booted in Safe Mode
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Explanation:

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DMA controllers ____.A) do not utilize an additional, special purpose, processorB) are a nonstandard component in PCs of todayC)
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Answer:

D) can access main memory at the same time as the main CPU

Explanation:

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