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romanna [79]
3 years ago
15

Lynette needs to make 2 birthday cards. Ellen needs to make 3 times as many. If y represents the number of cards Lynette need to

make, which expression shows how many more cards Ellen has to make compared to Lynette?
3y+y
3y(divided by)y
3y-y
3y*y
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

3y-y

Step-by-step explanation:

first you need to figure out how many cards Ellen needs to make. (3*2=6) but it ask how many more cards does she have to make then Lynette which means you then have to subtract how many cards Lynette is making from how many cards Ellen is making. (6-2) making the whole process. (3*2-2) now replace 2 with Y. (3y-y)

You might be interested in
Kevon Webster will bring hamburgers to grill. There are four patties per pound. He buys 28 pounds
Tcecarenko [31]

Answer:

112

Step-by-step explanation:

4x28=112

5 0
2 years ago
In an arithmetic​ sequence, the nth term an is given by the formula an=a1+(n−1)d​, where a1 is the first term and d is the commo
PilotLPTM [1.2K]

Answer:

105th term of given series is

a_n=\dfrac{105}{2}

Step-by-step explanation:

Given series is

\dfrac{1}{2},\ 1,\ \dfrac{3}{2},\ 2,\ \dfrac{5}{2}.....

As we can see,

\textrm{First term},a_1=\dfrac{1}{2}

Also,

1-\dfrac{1}{2}=\dfrac{3}{2}-1=2-\dfrac{3}{3}=.....=\dfrac{1}{2}

hence, we can say given series is in arithmetic progression,

with common difference,

d=\ \dfrac{1}{2}

As given in question the nth term in A.P is given by

a_n=a_1+(n-1)d

since we have to find the 105th term, so we can write

   a_{105}=\dfrac{1}{2}+(105-1)\dfrac{1}{2}

              =\dfrac{1}{2}+\dfrac{104}{2}

              =\dfrac{105}{2}

Hence, the 105th term of given series of A.P is \dfrac{105}{2}.

7 0
3 years ago
Topic: Recognizing Linear and Exponential and Quadratic Functions.
BigorU [14]

Answer:

  Recursive: f(1) = 1; f(n) = f(n-1)/3

  Equation: f(x) = 5/3·(1/3)^(x-1)

Step-by-step explanation:

You know this is an exponential function because sequential lines in the table have a common ratio of f(x) values:

  f(2)/f(1) = (5/9)/(5/3) = 3/9 = 1/3

  f(3)/f(2) = (5/27)/(5/9) = 9/27 = 1/3

and it continues like that.

Besides telling you the function is exponential, it also tells you that each term is 1/3 of the previous term.

<h3>Recursive formula</h3>

The value of f(1) is read from the table. For x = 1, that value is ...

  f(1) = 5/3

As we noticed above, each term is 1/3 the previous term, so the recursive relation is ...

  f(n) = (1/3)·f(n-1)

<h3>Equation</h3>

The general form of the equation for a geometric (exponential) relation is ...

  f(x) = f(1)·r^(x-1) . . . . . . where f(1) is the first term, and r is the common ratio

For this function, we have f(1) = 5/3 and r = 1/3, so the equation is ...

  f(x) = 5/3·(1/3)^(x-1)

__

<em>Additional comment</em>

When given values of x that count from 1, we often express the equation in terms of (x-1). That equation can be simplified so the exponent is x.

  f(x) = 5·(1/3)^x

5 0
1 year ago
Sarah jogged 4.8 miles each day for 22 days last month. How many miles did Sarah jog in total?
solong [7]

Answer:

105.6

hope this helps

have a good day :)

Step-by-step explanation:

8 0
3 years ago
Urgent help please
rosijanka [135]

Let's assume the frequency of sound be f and wave length is w.

Given that, the frequency of sound varies inversely as the wavelength.

So, we can set up an equation as following:

f*w = k Where k= constant of variation.

Other information is, the frequency of a musical note is 276 cycles per second when the wavelength is 1.2m.

So, next step is to plug in f = 276 and w = 1.2 in the above equation to get the value of k.

276 * 1.2 = k

So, k = 331.2

Next step is to plug in k = 331.2 in the above equation. So,

f * w = 331.2

Now we need to find the wave length : w when frequency : f = 600.

Therefore,

600 * w = 331.2

w = \frac{331.2}{600}

So, w = 0.552

Hence, the wave length is 0.552 m.

Hope this helps you!.

5 0
3 years ago
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