For this problem, we use the approach of ratio and proportion. Assuming that the given ratio of 444 days per 230 km is constant all throughout, we can determine the number of days or distance as long as one of the two is given. In this case, the solution is as follows:
444 days/230 km = 161616 days/distance
Distance = 83,720 km
Answer:
Step-by-step explanation:
If A is in between Y and Z, then;
YA+AZ = YZ
Given.
YA = 14x,
AZ = 10x and
YZ = 12x + 48
Substitute into the formula
14x+10x = 12x+48
Find x;
24x = 12x+48
24x-12x = 48
12x = 48
x = 48/12
x = 4
Get AZ
AZ = 10x
AZ =10(4)
AZ = 40
Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40
Answer:
-2
Step-by-step explanation:
Lets factor
(x+2)(x+2)=0
x=-2