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2 years ago

Scientists are trying to find chemicals that will be helpful to agriculture but which will not ____ the environment

Chemistry

1 answer:

Valentin [98]2 years ago

3 0

I think it is A. Harm

Scientists are trying to find chemicals that will be helpful to agriculture but which will not HARM the environment

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Which of the following describes an impact of the specific heat of water on the planet and the life forms that exist on it?

photoshop1234 [79]

Answer: D) sweat requires a lot of thermal energy to be absorbed to evaporate

Explanation:

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2 years ago

Read 2 more answers

Read the following chemical equation: Ti + 2Cl2 → TiCl4 Which statement best identifies and describes the reducing agent in the

goldenfox [79]

Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.

Explanation:

Firstly, we need to identify the reducing agent and the oxidizing agent.

The reducing agent: is the agent that has been oxidized via losing electrons.

The oxidizing agent: is the agent that has been reduced via gaining electrons.

Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.

So, Ti is the reducing agent because its oxidation state changes from 0 to +4.

Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.

Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.

4 0

3 years ago

In a constant‑pressure calorimeter, 70.0 mL of 0.310 M Ba ( OH ) 2 was added to 70.0 mL of 0.620 M HCl . The reaction caused the

Leno4ka [110]

Explanation:

Below are attachments containing the solution

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2 years ago

Write the expression for the equilibrium constant for the reaction represented by the equation CaCO3(s)⇌Ca2+(aq)+CO32−(aq). Is K

Alexeev081 [22]

<u>Answer:</u> For the given reaction, the value of $K_c$ is greater than 1

<u>Explanation:</u>

For the given chemical equation:

$CaCO3(s)\rightleftharpoons Ca^{2+}(aq.)+CO_3^{2-}(aq.)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]$

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression

As, the denominator is missing and the numerator is the only part left in the expression. So, the value of $K_c$ will be greater than 1.

Hence, for the given reaction, the value of $K_c$ is greater than 1

5 0

3 years ago

Cedrick & Astrid titrated a 10.00 mL aliquot of grapefruit juice with a 0.171 M NaOH solution to the end point. They calcula

Strike441 [17]

Answer:

17 mg/ml.

Explanation:

Since NaOH was titrated against Citric acid in the grape fruit, therefore

Converting g to mg,

0.1698 g * 1000 mg/1 g

= 169.8 mg

Volume of grapefruit juice = 10 ml

Mass of Citric acid in ml of juice = 169.8/10

= 17 mg/ml.

5 0

3 years ago