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notsponge [240]
3 years ago
8

Needed Help... for this work​

Chemistry
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

Displacement is the shortest distance travelled by a moving body through a entire journey.

The work done by the man pushing a fixed wall with the force of 100N is zero

work = force * displacement

Explanation:

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What are some good movies to watch on HBOMAX
Marina CMI [18]

Answer:

My Neighbor Totoro

Princess Mononoke

Pom Poko

Only Yesterday

Kiki's Delivery Service

Nausicaä of the Valley of the Wind

7 0
2 years ago
Read 2 more answers
25 g of NH, is mixed with 4 moles of O, in the given reaction:
FromTheMoon [43]

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

3 0
3 years ago
Read 2 more answers
The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80
ZanzabumX [31]
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

             A(t) = A(o) (1/2)^(t/d)

where t is the certain period of time. Substituting the known values,

             A(t) = (20 mg)(1/2)^(85.80/14.30)

Solving,

           A(t) = 0.3125 mg

Hence, the answer is 0.3125 mg. 
7 0
3 years ago
How many nickel atoms are in a nickel coin with a mass of 3.95g
lyudmila [28]

Answer:

4.05 × 10²² atoms

Explanation:

Step 1: Given data

Mass of nickel: 3.95 g

Step 2: Calculate the moles corresponding to 3.95 g of nickel

The molar mass of nickel is 58.69 g/mol.

3.95 g × (1 mol/58.69 g) = 0.0673 mol

Step 3: Calculate the atoms in 0.0673 moles of nickel

We will use Avogadro's number: there are 6.02 × 10²³ atoms of nickel in 1 mole of atoms of nickel.

0.0673 mol × (6.02 × 10²³ atoms/1 mol) = 4.05 × 10²² atoms

5 0
3 years ago
A scientist exam in two atoms. One has a nucleus with five protons in five neutron surrounded by five electrons. The other has a
grigory [225]

Answer:

C) They are not made of matter.

Explanation:

Case in which protons are inside of neutrons doesn't exist.

8 0
3 years ago
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