Answer:
this is called acid base reaction
Answer:
The new volume of the gas when the pressure is changed to 2.84 atm is 822.82 mL.
Explanation:
Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." That is, if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or
P * V = k
Assuming that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1*V1= P2*V2
In this case:
- P1= 9.86 atm
- V1= 237 mL
- P2= 2.84 atm
- V2=?
Replacing:
9.86 atm* 237 mL= 2.84 atm*V2
and solving you get:

V2= 822.82 mL
<u><em>The new volume of the gas when the pressure is changed to 2.84 atm is 822.82 mL.</em></u>
Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
Answer:
mass of excessive CO = 2.55 gram
Explanation:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
moles of Fe2O3 = mass / formula mass = 22.00/(56x2+16x3)=0.1375 (mol)
moles of CO = mass / formula mass = 14.1/(16+12) = 0.503
Fe2O3 reacts completely meanwhile CO is excessive.
mass of CO reacts = 3 x nFe2O3 x M = 3 x 0.1375 x (16+12) = 11.55 gram
mass of excessive CO = initial mass - reacted mass = 14.1 - 11.55 = 2.55 gram
Answer:
Mercury fulminate is very sensitive to shock, friction, and sparks. ... put mercury fulminate into blasting caps for detonating dynamite.
Explanation: