Gerry wants to construct a triangle with segments that are 4, 6, and 11 inches long. Is his triangle possible? Explain how you k
2 answers:
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Answer:
Step-by-step explanation:
We are given that
Length of flat piece of material=14 in
Width of flat piece of material=6 in
We have to find the volume of box as a function of x.
An open box is made from flat piece of material by cutting equal squares of length x from the corner and folding up the sides.
Therefore, Height of box=x in
Length of box=14-2x in
Width of box=6-2x in
We know that volume of box=
Using the formula
Volume of box=f(x)=
Answer:
Step-by-step explanation:
First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.
If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.
After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form
We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form
y = ±
Filling in our asymptotes as they were given to us:
y = ± where a is 2 and b is 1. Now we can write the formula for the hyperbola!:
which of course simplifies to