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3 years ago

Haley and her 4 friends decide to go out to dinner at Applebee's. The bill for their table came to $65.30. If they want to split

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

$13.06

Step-by-step explanation:

There are five people so 65.30/5 = 13.06

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A classroom board is 36 inches wide and 24 inches tall. Cheryl

Gennadij [26K]

Answer:

option B

Step-by-step explanation:

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3 years ago

Find the slope of the line whose equation is 8y-16x=12

Mice21 [21]

The formula for slope is y=mx+b
so if you re arrange the equation from 8y-16x=12
to 8y=16x+12
the slope will be the coefficient of x =16

5 0

3 years ago

Please help !!!!!!!!!

atroni [7]

Answer:

Katherine invested $12,000

Step-by-step explanation:

Use formula

$I=P\cdot r\cdot t,$

where

I = interest,

P = principal,

r = rate (as decimal),

t = time (in years).

In your case,

t = 1 year,

r = 0.06 (or 6%)

P + I =$12,720, thus

$12,720-P=P\cdot 0.06\cdot 1\\ \\12,720-P=0.06P\\ \\12,720=P+0.06P\\ \\1.06P=12,720\\ \\P=\dfrac{12,720}{1.06}\\ \\P=\$12,000\\ \\I=\$12,720-\$12,000=\$720$

6 0

3 years ago

Write an equation for the nth term of the geometric sequence 3584, 896, 224... Find the sixth term of this sequence

lions [1.4K]

Answer:

Step-by-step explanation:

r = $\frac{a_n}{a_{n-1}} = \frac{896}{3584} = \frac{1}{4}$

Using the geometric series formula for the <em>n</em>th term:

$S_n = a \cdot \frac{1-r^n}{1-r} => S_{6} = 3584 \cdot \frac{1 - (\frac{1}{4})^{6} }{1 - \frac{1}{4} } = 4777\frac{1}{2}$

4 0

3 years ago

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
$\implies f(x)=\dfrac1{(1-x)^2}$

5 0

3 years ago