Question

A reaction starts with 20.0 grams of lithium hydroxide (LiOH) and produces 31.0 grams of lithium chloride (LiCl), what is the percent yield of lithium chloride (LiCl)? *

Answer 1

Answer:

87.6%

Explanation:

Step 1:

The balanced equation for the reaction.

LiOH + HCl —> LiCl + H2O

Step 2:

Determination of the mass of LiOH that reacted and the mass of LiCl produced from the balanced equation.

This is illustrated below:

Molar mass of LiOH = 7 + 16 + 1 = 24g/mol

Mass of LiOH from the balanced equation = 1 x 24 = 24g

Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol

Mass of LiCl from the balanced equation = 1 x 42.5 = 42.5g

Thus, from the balanced equation, 24g of LiOH reacted to produce 42.5g of LiCl.

Step 3:

Determination of the theoretical yield of LiCl.

This is illustrated below:

From the balanced equation above,

24g of LiOH reacted to produce 42.5g of LiCl.

Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.4g

Therefore, the theoretical yield of LiCl is 35.4g.

Step 4:

Determination of the percentage yield of LiCl. This is illustrated below:

Actual yield of LiCl = 31g

Theoretical yield of LiCl = 35.4g

Percentage yield of LiCl =.?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 31/35.4 x 100

Percentage yield of LiCl = 87.6%