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butalik [34]
3 years ago
10

Balance these equations. NO LINKS!!

Chemistry
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

3 Cu (N O3)2 + 2 Al (O H)3 ---- 2 Al (N O3)3 + 3 Cu (O H) 2

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A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L. If the containe
Morgarella [4.7K]

Answer:

The pressure inside the container is 6.7 atm

Explanation:

We have the ideal gas equation: P x V = n x R x T

whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)

Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.

So we can calculate the pressure by

P = n x R x T / V

where as,

n = 41.1 g / 44 g/mol = 0.934 mol

Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm

3 0
3 years ago
There are two main characters of matter:
Oksana_A [137]
Mass and weight are the 2 main characters of matter
3 0
4 years ago
Which example is a container holding a heterogeneous mixture? * 1 point Bowl of clear chicken broth. Balloon filled with He gas.
Margarita [4]

Answer:

Bowl of clear chicken broth

Explanation:

A bowl of clear chicken broth is a heterogenous mixture.

  • A heterogenous mixture is one in which the constituents exists in at least two different phases.
  • A chicken broth is a heterogenous mixture which exists in the liquid - solid state.
  • The broth is made up of simmered meat, vegetables and other recipes together.

Such mixtures can be:

  1. Gas - liquids mixtures
  2. Liquid - solid mixtures
  3. Gas  - solid mixtures

A broth is an extract from cooking chicken. Some vegetables and extract are mixed together in a nutritious blend.

6 0
3 years ago
Calculate the morality of each of the following solutions: a. 15.4 g KCl in 289.2 mL solution b. 14.4 g of CaCl2 in 0.614 L solu
Nesterboy [21]
The answer is:
a. 0.712 M
b. 0.210 M
c. 0.336 M

Molarity is a measure of the concentration of solute in a solution.
It can be expressed as moles of solute ÷ volume of solution:
c = n ÷V
where:
c - concentration of solute,
n - moles of solute
V - volume of solution

n can be expressed as:
<span>n = m ÷ Mr
</span>where:
<span>n - moles of solute
</span>m - mass of solute
Mr - relative molecular mass

a. We know volume:
V = 289.2 mL = 0.2892 L
We need n and c.

n = m ÷ Mr
m = 15.4 g
Mr (<span>KCl) = 74.55 g/mol
n = </span>15.4 g ÷ <span>74.55 g/mol
n = 0.206 mol</span>

Thus, 
c = 0.206 mol ÷ <span>0.2892 L
c = 0.712 mol/L = 0.712 M

</span>b. We know volume:
V = 0.614 L
We need n and c.

n = m ÷ Mr
m = 14.4 g
Mr (CaCl₂<span>) = 110.98 g/mol
n = </span>14.4 g ÷ <span>110.98 g/mol
n = 0.129 mol</span>

Thus, 
c = 0.129 mol ÷ <span>0.614 L
c = 0.210 mol/L = 0.210 M
</span>
c. We can use formula:
m₁V₁ = m₂V₂
<span>m₁ = 3 M
</span><span>V₁ = 28 mL= 0.028 L
</span><span>m₂ = ?
</span><span>V₂ = 0.250 L
</span>Thus:
3 M × 0.028 L = m₂× <span>0.250 L
</span> m₂ = 0.336 M
4 0
3 years ago
How many oxygen atoms are contained in 2.74 g of Al2(SO4)3?
abruzzese [7]

Answer:

5.79 × 10^23 Oxygen atoms

Explanation:

Number of Oxygen atom in the compound = 4×3 = 12

Molar mass of Al2(SO4)3 = 342 g/mol.

No of mole = mass/molar mass = 2.74/342 = 8.01×10^-03 mole

2.74g of Al2(SO4)3 × 1 mole of Al2 (SO4)3 / 342g of Al2 (SO4)3 * 12 mole of Oxygen/ 1mole of Al(SO4)3 * 6.02×10^23 Oxygen atom/ 1 mole of Oxygen

= 5.79×10^23 Oxygen atoms

3 0
3 years ago
Read 2 more answers
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