Ask question

Ask question

All categories

2 years ago

15

What is the difference between metallic and non metallic oxides?

2 answers:

Sveta_85 [38]2 years ago

4 0

Answer:

Metal oxides are compounds composed of metal ions and oxide ions. Nonmetal oxides are compounds composed of nonmetal atoms and oxygen atoms. The main difference between metal oxides and non metal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.

Explanation:

have a great day ahead

tC

ladessa [460]2 years ago

3 0

Answer:

Metals react with oxygen to form metallic oxide while Nonmetals react with oxygen to form non-metallic oxide. metallic oxides are basic in nature while Nonmetallic oxides are acidic in nature.

Metal oxides are compounds composed of metal ions and oxide ions. Nonmetal oxides are compounds composed of nonmetal atoms and oxygen atoms. The main difference between metal oxides and non-metal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.

METALS:

Metals usually do not combine with hydrogen. Only a few reactive metals combine with hydrogen to form ionic metal hydrides.

--------------------------------------------------------------------

NON-METALS:
Non-metals react with hydrogen to form stable, covalent hydrides.

Explanation:

Have a great rest of your day
#TheWizzer

You might be interested in

PLEASE HELP!!!!!!!

dsp73

Answer: 1. $2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu$

2. 3 moles of $CuCl_2$ : 2 moles of $Al$

3. 0.33 moles of $CuCl_2$ : 0.92 moles of $Al$

4. $CuCl_2$ is the limiting reagent and $Al$ is the excess reagent.

5. Theoretical yield of $AlCl_3$ is 29.3 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles$

$\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles$

The balanced chemical equation is:

$2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu$

According to stoichiometry :

3 moles of $CuCl_2$ require = 2 moles of $Al$

Thus 0.33 moles of $CuCl_2$ will require= $\frac{2}{3}\times 0.33=0.22moles$ of $Al$

Thus $CuCl_2$ is the limiting reagent as it limits the formation of product and $Al$ is the excess reagent.

As 3 moles of $CuCl_2$ give = 2 moles of $AlCl_3$

Thus 0.33 moles of $CuCl_2$ give = $\frac{2}{3}\times 0.33=0.22moles$ of $AlCl_3$

Theoretical yield of $AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3$

Thus 29.3 g of aluminium chloride is formed.

5 0

2 years ago

How many electrons elements are present in period 2 ?

AVprozaik [17]

There are Eight elements

3 0

3 years ago

Read 2 more answers

A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Us

drek231 [11]

Answer:6.0M

Explanation:see attached photo

3 0

3 years ago

In an electric current, the ___ particles flow or are pushed along a path

MakcuM [25]

The negative particles flow or are pushed along a path

7 0

1 year ago

Yo what is the moon phases

Fynjy0 [20]

Answer:

New Moon, First Quarter, Full Moon, Last Quarter, Waxing Crescent, Waxing Gibbous, Waning Gibbous, and Waning Crescent.

8 0

2 years ago

Read 2 more answers