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Ket [755]
2 years ago
15

What is the difference between metallic and non metallic oxides?​

Chemistry
2 answers:
Sveta_85 [38]2 years ago
4 0

Answer:

Metal oxides are compounds composed of metal ions and oxide ions. Nonmetal oxides are compounds composed of nonmetal atoms and oxygen atoms. The main difference between metal oxides and non metal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.

Explanation:

have a great day ahead

tC

ladessa [460]2 years ago
3 0

Answer:

Metals react with oxygen to form metallic oxide while Nonmetals react with oxygen to form non-metallic oxide. metallic oxides are basic in nature while Nonmetallic oxides are acidic in nature.


Metal oxides are compounds composed of metal ions and oxide ions. Nonmetal oxides are compounds composed of nonmetal atoms and oxygen atoms. The main difference between metal oxides and non-metal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.



METALS:

Metals usually do not combine with hydrogen. Only a few reactive metals combine with hydrogen to form ionic metal hydrides.

--------------------------------------------------------------------

NON-METALS:
Non-metals react with hydrogen to form stable, covalent hydrides.







Explanation:

Have a great rest of your day
#TheWizzer

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Acetone is the main chemical in nail polish and has a density of 0.7857 g/mL. What is the volume of 6.54g of acetone ?
trapecia [35]

8.3mL

Explanation:

Given parameters:

Mass of acetone = 6.54g

Density of acetone = 0.7857 g/mL

Unknown:

Volume of acetone = ?

Solution:

Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:

  Density = \frac{Mass}{Volume}

Since the unknown is volume, we make it the subject of the formula

Volume =  \frac{mass}{density}

Input the values;

  Volume = \frac{6.54}{0.7857} = 8.3mL

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5 0
3 years ago
Identify the correct name for each compound.<br> NaOH:<br> CaSO4<br> NHACN:<br> Al2(SO4)3
klemol [59]

Answer:

Sodium hydroxide

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Ammonium cyanide

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Explanation:

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5 0
3 years ago
Which statement describes what it means for a planet’s orbit to be elliptical?(1 point)
sesenic [268]

Using the concepts of ellipse and the universal law of gravitation it can be found that the correct answer is:

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In the case of the sun and the planet, the sun is many orders of magnitude more massive than the planets, therefore, it is almost fixed in the center and the lighter planets rotate around it, where the sun is in the focus of the ellipse orbit.

In the special case that the two foci coincide, there is a circular movement, but the most general is that there is some separation between the foci, so the movement is elliptical with the sun located in one of the foci.

Let's analyze the claims of this exercise

a) True. When the orbit is not a perfect circle, you have an elliptical orbit, this is the most common case.

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c) False. Circular motion is a special case of elliptical motion when the two foci coincide

d) False. The axis of the planet influences the intensity of radiation reaching the surface, but not the shape of the orbit of the plant.

Using the concepts of ellipse it can be found that the correct answer is:

      a) The planet’s path around the sun is not a perfect circle and is shaped like an oval.

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3 0
2 years ago
A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
Fill in the blanks:
Misha Larkins [42]

Answer:

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