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Inga [223]
3 years ago
11

Why does reducing solute particle size increase the speed at which the solute dissolves in water? A. It exposes more of the solu

te to the water molecules. B. It makes the temperature of the water significantly higher. C. It raises the pressure of the water molecules on the solute. D. It makes the water molecules move around faster.
Chemistry
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:A

Explanation:For a given amount of solute, smaller particles have greater surface area. With greater surface area, there can be more contact between particles of solute and solvent.

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Answer:

Metal more reactive than non metal

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3 years ago
Help me I got stuck<br> Pls
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The answer is C because the weight is going down so they form a gas.
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Which organic prefix is matched with the number of carbon atoms that it represents?
Mandarinka [93]

Answer:heat-,7

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3 years ago
Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu
IrinaK [193]

Answer : The atomic radius for Ti is, 1.45\times 10^{-8}cm

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number (N_{A})=6.022\times 10^{23} mol^{-1}

First we have to calculate the volume of HCP crystal structure.

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times V} .............(1)

where,

\rho = density  = 4.51g/cm^3

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass  = 47.87 g/mole

(N_{A}) = Avogadro's number  

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}

V=1.06\times 10^{-22}cm^3

Now we have to calculate the atomic radius for Ti.

Formula used :

V=6R^2c\sqrt{3}

Given:

c/a ratio = 1.669 that means,  c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

V=6R^2\times (1.669a)\sqrt{3}

V=6R^2\times (1.669\times 2R)\sqrt{3}

V=(1.669)\times (12\sqrt{3})R^3

Now put all the given values in this formula, we get:

1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3

R=1.45\times 10^{-8}cm

Therefore, the atomic radius for Ti is, 1.45\times 10^{-8}cm

3 0
3 years ago
Which technique uses a special paper that separates a mixture into its different components with some components traveling a sho
iragen [17]
D. Liquid chromatography
5 0
3 years ago
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