Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
Answer: Undefined
Step-by-step explanation:
For this problem, we know that 3ˣ=-9. All we have to do is figure out what x is.
We know that any integer raised to the power cannot be negative. The closest answer we can get is x=2 because 3²=9. Unfortunately, we are looking for -9. Therefore, this x is undefined.
Answer: 2.1
Step-by-step explanation:
3.4 - 2.8d + 2.8d - 1.3
add the variables together and the coefficients or add the d's with d's and 3.4 with 1.3
= 3.4 - 1.3 = 2.1
=2.8d - 2.8d = 0
The final answer would be 2.1
Answer:
b≤3
Step-by-step explanation:
For this problem, you want to solve it similarly to linear equations.
We start with 4b+6≤18.
Subtracting 6 from both sides gives 4b≤12.
From there, in order to isolate the b, we must divide both sides by 4, leaving b≤3.
**This content involves solving linear inequalities, which you may wish to revise. I'm always happy to help!
Answer:
what's the question?
Step-by-step explanation:
