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Mars2501 [29]
2 years ago
13

Ms. Mor ris has 35 tests to grade this weekend. Mrs. Cook has 80% more tests than that to grade this weekend. How many tests doe

s Mrs. Cook have to grade?
Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

Mrs. Cook has to grade 63 tests.

Step-by-step explanation:

In order to find the answer, first you have to calculate 80% of the number of tests Ms. Morris has:

35*80%= 28

Then, you have to add the number that represents 80% to the number of tests Ms. Morris has to grade:

35+28=63

According to this, the answer is that Mrs. Cook has to grade 63 tests.

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How do you simply 2x+8=-6
photoshop1234 [79]
To simplify <span>2x + 8 = -6, the easiest way is to manipulate the equation one step at a time:

</span>2x + 8 = <span>-6
</span>2x = <span>-14             (subtract 8 from both sides)
</span>x = -7                 (divide both sides by 2)


3 0
3 years ago
Find the values of y = p(x) = √x for<br> x = 0, 1.44, 2.25, 3.24, 4.41, 5.29
zhenek [66]
P(x) = √x


for x = 0 → √0 = 0 and p(0) = 0
for x = 1.44 → √1.44 =1.2  and p(1.44) = 1.2
for x = 2.25 → √2.25 = 1.5 and p(2.25) = 1.5
for x = 3.24 → √3.24 = 1.8 and p(3.24) = 1.8
for x = 4.41 → √4.41=  2.1 and p(4.41) = 2.1
for x = 5.29 → √5.29 = 2.3 and p(5.29) = 2.3

6 0
3 years ago
What is the slope of the line?
postnew [5]

Answer:\frac{3}{10}

Step-by-step explanation:

\frac{1.5}{5} simplifies if you divide by .5 to \frac{3}{10}

7 0
2 years ago
How do i solve that question?
yawa3891 [41]

a) The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }.

b) The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}.

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}.

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable (y, t) in each side of the identity:

6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t (1)

6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C

Where C is the integration constant.

By table of integrals we find the solution for each integral:

-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C

If we know that x = 0 and y = 1<em>, </em>then the integration constant is C = -2.

The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }. \blacksquare

b) In this case we need to solve a first order ordinary differential equation of the following form:

\frac{dy}{dx} + p(x) \cdot y = q(x) (2)

Where:

  • p(x) - Integrating factor
  • q(x) - Particular function

Hence, the ordinary differential equation is equivalent to this form:

\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x} (3)

The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}. \blacksquare

The solution for (2) is presented below:

y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C (4)

Where C is the integration constant.

If we know that p(x) = -\frac{1}{x} and q(x) = x^{2} + \frac{1}{x}, then the solution of the ordinary differential equation is:

y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C

y = x\int {x} \, dx + x\int\, dx + C

y = \frac{x^{3}}{2}+x^{2}+C

If we know that x = 1 and y = -1, then the particular solution is:

y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}. \blacksquare

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0
2 years ago
What is the location of point g, which partitions the directed line segment from d to f into a 5:4 ratio? a number line goes fro
Zarrin [17]

Using proportions, according to the ratio of the partition, it is found that the location of point g is at 3.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, point g partitions the directed line segment from d to f into a 5:4 ratio, hence:

g - d = \frac{5}{9}(f - d)

We have that d = -2 and f = 7, hence:

g - d = \frac{5}{9}(f - d)

g + 2 = \frac{5}{9}(7 + 2)

g + 2 = 5.

g = 3.

More can be learned about proportions at brainly.com/question/24372153

#SPJ4

4 0
2 years ago
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