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Nuetrik [128]
2 years ago
15

When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache

d terminal speed Group of answer choices his acceleration is equal to g. the force of air drag on him is equal to zero. the force of air drag on him is equal to g. his speed is equal to g. None of the above choices are correct the force of air drag on him is equal to his weight.
Physics
1 answer:
GenaCL600 [577]2 years ago
6 0

Answer:

None of the above forces on air drag on him is equal to his weight

Explanation:

In the velocity-time graph,the gradient of the curve where it is flatten shows the parachutist reaches the terminal velocity when it reaches terminal velocity which means the parachutist reaches constant velocity or speed,indicating that the acceleration of free fall(g) is zero.And according to the resultant force formula weight - air drag= mass*acceleration. so when accelerate is zero,resultant force is zero. And hence the equation will be like this: weight= air drag

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Why do sound waves travel around corners better than light waves? Sound<br>waves<br>​
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Answer:

Sound waves travel at 343 m/s through the air and faster through liquids and solids. The waves transfer energy from the source of the sound, e.g. a drum, to its surroundings. Your ear detects sound waves when vibrating air particles cause your ear drum to vibrate. The bigger the vibrations the louder the sound.

8 0
3 years ago
A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, what happens to
maria [59]

Answer:

the distance between interference fringes increases

Explanation:

For double-slit interference, the distance of the m-order maximum from the centre of the distant screen is

y=\frac{m \lambda D}{d}

where \lambda is the wavelength, D is the distance of the screen, and d the distance between the slits. The distance between two consecutive fringes (m and m+1) will be therefore

\Delta y = \frac{(m+1) \lambda D}{d}-\frac{m \lambda D}{d}=\frac{\lambda D}{d}

and we see that it inversely proportional to the distance between the slits, d. Therefore, when the separation between the slits decreases, the distance between the interference fringes increases.

4 0
3 years ago
A 24 kg child slides down a 3.3-m-high playground slide. She starts from rest, and her speed at the bottom is 3.0 m/s.a. What en
Gelneren [198K]

Answer:

(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

(b) U=668.16\ J

Explanation:

Given:

  • mass of the child, m=24\ kg
  • height of the slide, h=3.3\ m
  • initial velocity of the child at the slide, v_i=0 m.s^{-1}
  • final velocity of the child at the bottom of slide, v_f=3\ m.s^{-1}

(a)

∴The initial potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

Initial potential energy:

PE=m.g.h

PE=24\times 9.8\times 3.3

PE=776.16\ J

Kinetic energy at the bottom of the slide:

KE=\frac{1}{2} m.v^2

KE= 0.5\times 24\times 3^2

KE= 108\ J

(b)

Now, the difference in the potential and kinetic energy is the total change in the thermal energy of the slide and the seat of her pants.

This can be given as:

U=PE-KE

U=776.16-108

U=668.16\ J

4 0
3 years ago
We have an object moving at 5 m/s with mass 5 kg. It undergoes a quick collision with some other object and now moves at 1 m/s.
andrey2020 [161]

Answer:

-20 kg.m/s

Explanation:

We have an object moving at 5 m/s with mass 5 kg. The initial momentum is:

pi = m × vi

pi = 5 kg × 5 m/s = 25 kg.m/s

It undergoes a quick collision with some other object and now moves at 1 m/s. The final momentum is:

pf = m × vf

pf = 5 kg × 1 m/s = 5 kg.m/s

The change in the object's momentum is:

Δp = pf - pi

Δp = 5 kg.m/s - 25 kg.m/s = -20 kg.m/s

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The most important factor in determining the development oflife on earth is
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Earth's distance from the sun it effects every living being on the Earth.
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