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Sindrei [870]
3 years ago
13

Select the correct answer. Two charged objects, A and B, exert an electric force on each other. What happens if the distance bet

ween them is increased? OA The charge on B decreases. OB The charge on B increases. OC The electric force between them decreases. OD. The electric force between them increases.​
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

OC The electric force between them decreases.

Explanation:

Electric force is a force due to charges which charged objects exert on each other. The charged objects A and B thus exert a definite force on each other which its value can be varied by varying the distance between them.

It is goo to note that the force between two charges is inversely proportional the the square of the distance between them. Thus when the distance is increased, the electric force would decease.

In the given question, option C is appropriate.

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A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the
xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2

\hat{ECD} = tan^{-1} 2 = 63.43^o

This is also the angle ACB, so we can find the length AB:

tan(\hat{ACB}) = \frac{AB}{AC} = \frac{AB}{234}

2 = \frac{AB}{234}

AB = 2*234 = 468 m

So the height of the building is 468m

5 0
3 years ago
A projectile is launched from the ground with an initial velocity of 12ms at an angle of 30° above the horizontal. The projectil
netineya [11]

vi^{2}sin2thita/g =12^{2}sin2[30]/9.8=12.7Answer:

Explanation:

range is given as

6 0
3 years ago
Read 2 more answers
Mia wanted to know how Earth’s movements created new landforms. She decided to read about folded mountains and their characteris
kifflom [539]

Answer:

I’m pretty sure it’s D

Explanation:

the crust breaks and shifts when that happens

hope dis helps ^-^

5 0
3 years ago
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"A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at
MrRissso [65]

Answer:

life (N) of the specimen is 117000  cycles

Explanation:

given data

ultimate strength Su = 120 kpsi

stress amplitude σa = 70 kpsi

solution

we first calculate the endurance limit of specimen Se i.e

Se = 0.5× Su   .............1

Se = 0.5 × 120

Se = 60 kpsi

and we know strength of friction f  = 0.82

and we take endurance limit Se is = 60 kpsi

so here coefficient value (a) will be

a = \frac{(f\times Su)^2}{Se}     ......................1  

put here value and we get

a = \frac{(0.82\times 120)^2}{60}  

a = 161.4  kpsi

so coefficient value (b) will be

b = -\frac{1}{3}log\frac{(f\times Su)}{Se}  

b =  -\frac{1}{3}log\frac{(0.82\times 120)}{60}  

b = −0.0716

so here number of cycle N will be  

N =  (\frac{ \sigma a}{a})^{1/b}

put here value  and we get

N =  (\frac{ 70}{161.4})^{1/-0.0716}

N = 117000

so life (N) of the specimen is 117000  cycles

7 0
3 years ago
What is the mass of an object that has an acceleration of 2.63 m/s^2 when an unbalanced force of 112 N is applied to it?
shusha [124]
112/2.63= 42.586
42.586 is your answer I need 20 characters
6 0
3 years ago
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