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Sindrei [870]
3 years ago
13

Select the correct answer. Two charged objects, A and B, exert an electric force on each other. What happens if the distance bet

ween them is increased? OA The charge on B decreases. OB The charge on B increases. OC The electric force between them decreases. OD. The electric force between them increases.​
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

OC The electric force between them decreases.

Explanation:

Electric force is a force due to charges which charged objects exert on each other. The charged objects A and B thus exert a definite force on each other which its value can be varied by varying the distance between them.

It is goo to note that the force between two charges is inversely proportional the the square of the distance between them. Thus when the distance is increased, the electric force would decease.

In the given question, option C is appropriate.

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A planet or butting a distant star has been observed to have an orbital period of 0.76 earth years at a distance of 1.2 au. What
NNADVOKAT [17]

Answer:

The mass of the star is, M = 5.9567x10³⁰ Kg

Explanation:

Given

The orbital period of the planet, T = 0.76 year

                                                        = 2.3967x10⁷ seconds

The distance between planet and sun, R+h = 1.2 a.u

                                                                        = 1.795 x 10¹¹ meters

The orbital period of the planet is given by the formula

                                 T={2\pi\sqrt{\frac{(R+h)^{2}}{GM}}}

Squaring and solving for M

                                   M=\frac{4\pi ^{2} (R+h)^{3}}{GT^{2} }

Substituting the given values in the above equation

                          M=\frac{4\pi ^{2}(1.795X10^{11} )^{3} }{6.673X10^{-11}X(2.3967X10^{7})^{2}}    

                                     M = 5.9567 x 10³⁰ Kg

Hence, the mass of the star the planet is orbiting, M = 5.9567 x 10³⁰ Kg

6 0
3 years ago
I need help with this problem on science 8th grade here is the picture of the assignment place help me
Leni [432]

Answer:

the first one is D

Explanation:

so if the others u put are right the the second would be c

7 0
3 years ago
Read 2 more answers
a golf ball is hit with a velocity of 30.0 m/s at an angle of 25 degrees about the horizontal. how long is the ball in the air a
Pie
Ok so use trigonometry to work out the vertical component of velocity.

sin(25) =opp/hyp
rearrange to:
30*sin(25) which equals 12.67ms^-1

now use SUVAT to get the time of flight from the vertical component,

V=U+at

Where V is velocity, U is the initial velocity, a is acceleration due to gravity or g. and t is the time.

rearranges to t= (V+u)/a

plug in some numbers and do some maths and we get 2.583s

this is the total air time of the golf ball.

now we can use Pythagoras to get the horizontal component of velocity.

30^2-12.67^2= 739.29
sqrt739.29 = 27.19ms^-1

and finally speed = distance/time

so--- 27.19ms^-1*2.583s= 70.24m

The ball makes it to the green, and the air time is 2.58s 
4 0
3 years ago
What is the pressure at 5000 km below the surface of the earth
attashe74 [19]

Answer:

The centre of the earth is harder to study than the centre of the sun." Temperatures in the lower mantle the reach around 3,000-3,500 degrees Celsius and the barometer reads about 125 gigapascals, about one and a quarter million times atmospheric pressure.

Explanation:

7 0
3 years ago
A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is
Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

<u>brainly.com/question/13834772</u>

#SPJ4

7 0
2 years ago
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