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3 years ago

HURRRRRRRRRRRYYYYYYYYYYYYYYYYYYYYY

Physics

1 answer:

telo118 [61]3 years ago

7 0

I’m thinking C, Solid but I’m not very sure

I really hopes this helps

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Help pls! Explain if you think we should continue to use geothermal power in the future

zhuklara [117]

Answer:

Geothermal power can provide consistent electricity throughout the day and year - continuous baseload power and flexible power to support the needs of variable renewable energy resources, such as wind and solar. Sustainable Investment.

Explanation:

THIS IS WHY WE SHOULD USE GEOTHERMAL ENERGY IN FUTURE

YOU CAN MARK ME AS BRAINIEST IF YOU WANT

4 0

3 years ago

Explain how the gravitational potential energy of an object can be changed.

inna [77]

Answer:

Change in Potential energy, pe = Final potential energy - Initial potential energy

Explanation:

∆p.e = Final p.e - Initial p.e

From the equation ∆p.e = (mgh) final - (mgh) initial

4 0

3 years ago

This is the build up of substance such as pesticides in an organism and occurs when an organism absorb a substance at a rate fas

GuDViN [60]

Answer:

which the substance is lost by catabolism and excretion.

Explanation:

3 0

3 years ago

A magnifying glass has a converging lens of focal length of 13.8 cm. At what distance from a nickel should you hold this lens to

Colt1911 [192]

Answer:

19.6 cm.

Explanation:

From the question given above, the following data were obtained:

Focal length (f) = 13.8 cm

Magnification (M) = +2.37

Object distance (u) =.?

Next, we shall determine the image distance. This can be obtained as follow:

Magnification (M) = +2.37

Object distance (u) = u

Image distance (v) =?

M = v / u

2.37 = v / u

Cross multiply

v = 2.37 × u

v = 2.37u

Finally, we shall determine the object distance. This can be obtained as follow:

Focal length (f) = 13.8 cm

Image distance (v) = 2.37u

Object distance (u) =.?

1/v + 1/u = 1/f

vu / v + u = f

2.37u × u / 2.37u + u = 13.8

2.37u² / 3.37u = 13.8

Cross multiply

2.37u² = 3.37u × 13.8

2.37u² = 46.506u

Divide both side by u

2.37u² / u = 46.506u / u

2.37u = 46.506

Divide both side by 2.37

u = 46.506 / 2.37

u = 19.6 cm

Thus, the lens should be held at a distance of 19.6 cm.

7 0

3 years ago

A pure copper sphere has a radius of 0.935 in. How many copper atoms does it contain? [The volume of a sphere is (4>3)pr3 and

ValentinkaMS [17]

Answer:

47.68 x 10²³ or 4.768 x 10²⁴ copper atoms

Explanation:

Given:

Radius of the copper sphere (r) = 0.935 in

First convert the radius from inches to centimeters

1 in = 2.54cm

0.935in = 0.935 x 2.54cm = 2.3749cm

∴ r = 2.3749cm

Calculate the volume of the copper sphere as follows

Volume = $\frac{4}{3}\pi r^{3}$ [substitute r = 2.3749cm and π = 22 / 7]

Volume = $\frac{4}{3}(\frac{22}{7} ) (2.3749)^{3}$

Volume = 56.108cm³

From the volume and given density, calculate the mass of the copper sphere

mass = density x volume [density = 8.96g/cm³]

mass = 8.96 x 56.108 = 502.73g

From known facts

1 mole of copper = 63.5g of copper = 6.022 x 10²³ copper atoms.

Then,

502.73 g of copper = $\frac{502.73 * 6.022*10^{23}}{63.5}$ = 47.68 x 10²³ copper atoms

Therefore, the sphere contains 47.68 x 10²³ copper atoms

6 0

4 years ago

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