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Sophie [7]
3 years ago
13

I don’t even know where to begin on this one

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

This is simple linear regression analysis. We can determine the line of best fit using technology

Step-by-step explanation:

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ASAP HELP
ELEN [110]
-11 is the answer

2(-2)-3(3)-(-2)
-4-9+2
-13+2
-11
3 0
3 years ago
Which is closest to the distance between the two points on the graph?
SVETLANKA909090 [29]

Answer:

25

Step-by-step explanation:

6 0
3 years ago
How many solutions does the equation 5x+17=4(3x−1) have?
Stella [2.4K]

<u>Answer:</u>

one solution = 3

<u>Step-by-step explanation:</u>

Let's solve your equation step-by-step.

5x+17=4(3x−1)

Step 1: Simplify both sides of the equation.

5x+17=4(3x−1)

5x+17=(4)(3x)+(4)(−1)(Distribute)

5x+17=12x+−4

5x+17=12x−4

Step 2: Subtract 12x from both sides.

5x+17−12x=12x−4−12x

−7x+17=−4

Step 3: Subtract 17 from both sides.

−7x+17−17=−4−17

−7x=−21

Step 4: Divide both sides by -7

-7x/-7 = -21/-7 = 3

4 0
3 years ago
State whether the equation is true, false or open? 4y+8=6y+3
g100num [7]

<u><em>Answer:</em></u>

Open


<u><em>Explanation:</em></u>

An open equation is an equation that has variables and CAN be solved

<u>Example</u>: 2x = 4 ......> can be solved giving ......> x = 2

A false equation is one where both sides can NEVER be equal

<u>Example:</u> 15 = 2(3) + 1 ..........> 15 can never be equal to 7

A true equation is one having no variables and both sides are ALWAYS equal

<u>Example:</u> 2(3) + 1 = 2(2) + 3 ........> 7 will always be equal to 7


Now, the given equation is:

4y + 8 = 6y + 3

Let's try to solve is:

4y + 8 = 6y + 3

6y - 4y = 8 - 3

2y = 5

y = 2.5


Therefore, the given equation contains a variable and can be solved which means that it is an open equation


Hope this helps :)

8 0
3 years ago
Read 2 more answers
Amber and her friend Nathan are saving to buy a video game that costs $65. Amber earns $12 per week for babysitting and spends $
Vika [28.1K]
Answer:65 divided [(12-4)+(15-8)]
7 0
3 years ago
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