Lizette is training for a marathon. At 7:00 she left her house and ran until 8:30, then she walked until 11:30. She covered a to
2 answers:
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ANSWER
The approximate solution is
EXPLANATION
The point of intersection of the two lines is the solution of the linear systems represented by the graph.
From the graph we can determine that each box is 2 units.
From the graph, when we start at O and count two boxes to the right and half box down, we obtain the point of intersection of the two lines to be
Note that since each box is two units, half way between the boxes gives one unit.
The approximate solution is
EXPLANATION
The point of intersection of the two lines is the solution of the linear systems represented by the graph.
From the graph we can determine that each box is 2 units.
From the graph, when we start at O and count two boxes to the right and half box down, we obtain the point of intersection of the two lines to be
Note that since each box is two units, half way between the boxes gives one unit.
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so .
What is the probability that a line width is greater than 0.62 micrometer?
That is
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.