The fraction of a circle represented by the shaded region is:
S '/ S = ((8/5) * pi * r) / (2 * pi * r)
Rewriting we have:
S '/ S = ((8/5)) / (2)
S '/ S = 8/10
S '/ S = 4/5
Then, we can make the following rule of three:
(64/5) pi -------> 4/5
x ----------------> 1
Clearing x we have:
x = ((1) / (4/5)) * ((64/5) pi)
Rewriting:
x = (5/4) * ((64/5) pi)
x = (5/4) * ((64/5) pi)
x = 50.24
Answer:
The area of the complete circle is:
x = 50.24
Answer:
hiiii
Step-by-step explanation:
but u have posted all the pictures upside down so can't understand anything
The friction force exerted on the 2400kg car is 9408 Newtons
<h3>
What force will be exerted on the 2400kg car?</h3>
First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:
F = k*M
Where F is the force, M is the mass and k is the constant of proportionality.
We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:
6272N = k*1600kg
Solving for k we get:
k = (6272N)/(1600 kg) = 3.92 N/kg
Then the proportional relationship is:
F = (3.92 N/kg)*M
So if M = 2400kg, we have:
F = (3.92 N/kg)*2400kg = 9408 N
So the friction force exerted on the 2400kg car is 9408 Newtons
If you want to learn more about proportional realtions:
brainly.com/question/12242745
#SPJ1
