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Alja [10]
3 years ago
7

Which of the following correctly describes the importance of the nitrogen cycle?

Biology
1 answer:
Stella [2.4K]3 years ago
8 0
The answer is D To create ammonia needed by plants to create proteins.
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Choose all the answers that apply. Sex-linked disorders _____. affect males more than females, affect females more than males, c
Wittaler [7]

Several are correct:

Affect males more than females

Can be carried by females

Are always expressed by males


A bit of explanation: sex linked genes are carried on the X chromosome. That’s why it affects males more than females...they only get one x from their mom. Females can be affected IF they receive 2 bad X chromosomes. So with a male, the bad gene on the x is always expressed. Color blindness is a good example of this.

7 0
3 years ago
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Which characteristic is common to all inner planets?
olchik [2.2K]

Answer:

They all have solid, rocky surfaces.

Explanation:

7 0
4 years ago
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Beyonce has a straight hairline, which is a recessive trait. Bruno also has a straight hairline. What is the chance that their c
Andrej [43]
0% because if straight hairline is recessive that means it would need 2. Since, Widows peak seems to be dominant, then there would need to be at least 1 dominant. But, there are both people that have recessive traits.
8 0
2 years ago
How do I NSTANTANEOUS speed and average speed differ
qaws [65]

Answer:

Instantaneous speed is found by taking the absolute value of instantaneous velocity, and it is always positive. Average speed is the total distance traveled divided by elapsed time.

5 0
2 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
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