Six congruent isosceles triangles would be named as their letters (must be in order!) then isosceles.
Please message me!!
7^4/7^6
2401/117649
0.02040816
The answer is:0.020408
Answer:
<em>h</em><em> </em><em>(</em><em>x</em><em>)</em><em> </em><em>=</em><em> </em><em>f</em><em> </em><em> </em><em>(</em><em>x</em><em>)</em><em>.</em><em>g</em><em> </em><em>(</em><em>x</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em> </em><em>(</em><em>-</em><em>2</em><em>)</em><em>(</em><em>5x</em><em>-</em><em>6</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>10</em><em>x</em><em> </em><em>+</em><em> </em><em>12</em>
<em>#</em><em>$</em><em>#</em><em> </em><em>THANK</em><em> </em><em>YOU</em><em> </em><em>#</em><em>$</em><em>#</em>
Answer:
its A=(-4,2)
Step-by-step explanation:
First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at
, the equation will contain a
term.
If we start with
we have a parabola, concave down, with vertex at
and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have

Now we only have to fix the fact that this parabola doesn't land at
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

such that:
Plugging these values gets us

As you can see in the attached figure, the parabola we get satisfies all the requests.