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BlackZzzverrR [31]
3 years ago
8

Help me plz the answer is d right i dont reamber

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0

Answer:

C. The total amount spent on drinks by Andrew.

Step-by-step explanation:

y itself would be the number of drinks purchased, and 2.5 is the cost. And since is is 2.5y then it represents the total amount.

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A manufacturing plant earned $80 per man hour of labor when it opened Each year, the plant carns an
galina1969 [7]

Answer: 16

Step-by-step explanation:

80 divided by 5 equals 16

6 0
3 years ago
Here is a tape diagram representing the ratio of red paint to yellow paint in a mixture of orange paint.
Vinvika [58]

Answer:

2:3

Step-by-step explanation:

So there are 9 cups of red paint

There are 6 cups of yellow paint

Now we need yellow:red

6:9

Simplify it

2:3

So the ratio is 2:3 for yellow to red paint

3 0
3 years ago
The best answer gets brainiest please help!
vazorg [7]

Answer: 1) 10x+y=7

2) 3x-y=3

x-y=1

5 0
3 years ago
Read 2 more answers
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
Express 150% of 60% as a percent.
photoshop1234 [79]

Answer:

0.9 ≈ 90%

Step-by-step explanation:

60% = 60/100

150% of 60% = 150/100 * 60/100

= 9000/10000

= 0.9 ≈ 90%

7 0
3 years ago
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