Let f(x) = 2x3 – 4x. Find f(-2).

Mathematics

2 answers:

N76 [4]3 years ago

7 0

Answer:

Step-by-step explanation:

f(x) = 2x^3 - 4x.....find f(-2).....so sub in -2 for x

f(-2) = 2(-2^3) - 4(-2)

f(-2) = 2(-8) + 8

f(-2) = -16 + 8

f(-2) = -8 <==

djverab [1.8K]3 years ago

6 0

We have $f(x)=2x^3-4x$ , to find $f(-2)$ put -2 instead of x, $f(-2)=2(-2)^3-4(-2)=-16+8=\boxed{-8}$ .

Hope this helps.

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Answer:

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2 years ago

Read 2 more answers

Find the complex zeros of x^3+27. write f in factored form

aliina [53]

$x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0

$