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3 years ago

I don't know what to do.

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

3 0

Answer:

13 Compute using the 2 right angles, we know that m<FIG=90* and

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1. Which value is a solution of the equation 3-2x=-5?

Ivan

#1)
-5-3=-8
-2x=-8
x=4

#2
D.) 5-2=3

#3
D.) 5×-2=-10

6 0

3 years ago

Read 2 more answers

What is used to locate points in the coordinate plane

Maru [420]

The x axis and the y axis

3 0

4 years ago

H=32-2t-5t^2

Andrej [43]

Answer: The answer is t = 2.34 seconds. Explanation: An explanation is provided in the image(P.S. The handwriting in this is not great as it was drawn online).

6 0

2 years ago

The NAR estimates that 23% of all homes purchased in 2004 were considered investment properties. If a sample of 800 homes sold i

Natali [406]

Answer: 0.7752

Step-by-step explanation:

Given : The proportion of all homes purchased in 2004 were considered investment properties estimated by NAR: p = 0.23

Sample size : n= 800

Required sample proportion : $\dfrac{175}{800}=0.21875$

Now , the probability that at least 175 homes are going to be used as investments will be :

$P(p\geq 0.21875)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\geq\dfrac{0.21875-0.23}{\sqrt{\dfrac{0.23(1-0.23)}{800}}})\\\\=P(z\geq-0.756)\ \ [\because\ z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\=P(z-z)=P(Z$ [using p-value calculator or z-table]

Hence, the required probability = 0.7752

8 0

4 years ago

Membership in an elite organization requires a test score in the upper 30% range. If the mean is equal to 115 and the standard d

Olenka [21]

Answer:

Lowest acceptable score = 121.3

Step-by-step explanation:

Mean test score (μ) = 115

Standard deviation (σ) = 12

The z-score for any given test score 'X' is defined as:

$z=\frac{X-\mu}{\sigma}$

In this situation, the organization is looking for people who scored in the upper 30% range, that is, people at or above the 70-th percentile of the normally distributed scores. At the 70-th percentile, the corresponding z-score is 0.525 (obtained from a z-score table). The minimum score, X, that would enable a candidate to apply for membership is:

$0.525=\frac{X-115}{12}\\X=121.3$

4 0

4 years ago