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Elza [17]
2 years ago
7

If the point (-2, 5) is reflected across the y-axis, its image will be at (-2, -5). true false

Mathematics
1 answer:
Ivan2 years ago
3 0
False, the image will be (+2; 5)
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What is the value of (−23) –[(−25) – {(−17) –(−19)}
o-na [289]
The answer is four.
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2 years ago
49 - 3 + 9 times 8 divided by 2
irinina [24]

Answer:

82

Step-by-step explanation:

49 - 3 + 9 times 8 divided by 2

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3 years ago
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What is the equation for​
WARRIOR [948]

The equation of a line that is perpendicular to the given line is y = –4x – 16.

Solution:

The equation of a line given is y = 0.25x – 7

Slope of the given line(m_1) = 0.25

Let m_2 be the slope of the perpendicular line.

Passes through the point (–6, 8).

<em>If two lines are perpendicular then the product of the slopes equal to –1.</em>

\Rightarrow m_1 \cdot m_2=-1

\Rightarrow 0.25\cdot m_2=-1

\Rightarrow m_2=\frac{-1}{0.25}

\Rightarrow m_2=-4

Point-slope intercept formula:

y-y_1=m(x-x_1)

x_1=-6, y_1=8 and m=-4

Substitute these in the formula, we get

y-8=-4(x-(-6))

y-8=-4(x+6)

y-8=-4x-24

Add 8 on both sides of the equation.

y-8+8=-4x-24+8

y=-4x-16

Hence the equation of a line that is perpendicular to the given line is

y = –4x – 16

5 0
3 years ago
Let f(x)=x^3 and g(x)= √x, and h(x)=x/3. Find each of the following: f(g(h(6)))
rewona [7]

Answer:

go from inside out.

h(x)=x/3

(\sqrt{2})^{3}=> h(6) = 6/3 = 2

g(x) = \sqrt{x}

=> g(h(6)) = g(2) = \sqrt{2}

f(x) = x^{3}

=> f(g(h(6))) = f(\sqrt{2} ) = (\sqrt{2} )^{3}

6 0
3 years ago
Please help I'm on a test right now!!​
Svetach [21]
The answer would be 7-x.
8 0
2 years ago
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